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frosja888 [35]
3 years ago
13

How many total electrons can be contained in the 4f sublevel?

Chemistry
1 answer:
olga55 [171]3 years ago
7 0
The correct answer should be 14.

Since an f-subshell can only have 7 orbitals and each orbital can only hold 2 electrons, that means that a 4f sublevel can only have 14 electrons.
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Help with this worksheet please (24pts)
Igoryamba
  • Atoms that loss or gain electrons are called ions. There are two types of ions: cations and anions.
  • Here, 2+ represents that Calcium (Ca) should gain 2 more electrons so that its number equals to that of protons.
  • 3- represents that Nitrogen (N) should loss 3 electrons to equivalent with the number of protons.
  • Here, anions are S^2-, P^3-, Se^2-, Br^-.
  • While cations are Cr^3+, Ag^+, Li^+, Ba^2+.
  • The number of protons of Magnesium (Mg) = 12
  • The number of nuetrons of Mg = 12
  • The number of electrons of Mg = 12

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
2 years ago
Question 6 (4 points)
pishuonlain [190]

Answer:

20.9%

Explanation:

I took the test i hope this helps:)

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2 years ago
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Pepsi [2]

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i think niether

Explanation:

5 0
2 years ago
At 40 Centigrade kW is?
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yee

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3 0
3 years ago
A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o
taurus [48]

Answer:

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

Atomic mass of the elements are:

Na: 22.989 u

S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole(s) of Na2S2O3 = (mass taken)/(molar mass)

= (17.240 g)/(158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)

= 0.05029 L.

To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

= (moles of sodium thiosulfate)/(volume of solution in L)

= (0.1090 mole)/(0.05029 L)

= 2.1674 mol/L

6 0
3 years ago
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