Explanation: c= 1.2 mol/l (concentration ) and V = volume.
Amount of substance n= cV. Also n = mass/ molar mass m/M.
You need further information to solve the problem.
Either mass or amount of substance of HNO3 Is missing
Answer:
the change in energy of the gas mixture during the reaction is 227Kj
Explanation:
THIS IS THE COMPLETE QUESTION BELOW
Measurements show that the enthalpy of a mixture of gaseous reactants increases by 319kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that -92kJ of work is done on the mixture during the reaction. Calculate the change of energy of the gas mixture during the reaction in kJ.
From thermodynamics
ΔE= q + w
Where w= workdone on the system or by the system
q= heat added or remove
ΔE= change in the internal energy
q=+ 319kJ ( absorbed heat is + ve
w= -92kJ
If we substitute the given values,
ΔE= 319 + (-92)= 227 Kj
With the increase in enthalpy and there is absorbed heat, hence the reaction is an endothermic reaction.
The balanced equation for the reaction is;
<span>2HNO</span>₃<span> + Ag ---> NO + 2H</span>₂O<span> + AgNO</span>₃
Stoichiometry of HNO₃ to Ag is 2:1
we need to first find the limiting reactant
number of HNO₃ moles - 12.6 g / 63 g/mol = 0.2 mol
number of Ag moles - 10.8 g / 108 g/mol = 0.1 mol
0.2 moles of HNO₃ react with 0.1 mol of Ag, this is in the 2:1 molar ratio which means that both reactants react fully in the reaction.
then molar ratio of Ag to NO is 1:1
number of Ag moles equivalent to number of NO moles
Number of NO moles - 0.1 mol
Mass of NO - 0.1 mol x 30 g/mol = 3 g
mass of NO produced is 3 g
Answer:
0,33atm
Explanation:
For the reaction:
NH₄HS(s) ⇌ H₂S(g) + NH₃(g)
kp is defined as:
kp = 0.11 = P(H₂S) P(NH₃) <em>(1)</em>
Where P(H₂S) and P(NH₃) are partial pressures of each compound.
In equilibrium, if in your system the only addition is of NH₄HS(s), the partial pressures and the concentration of each compound are:
NH₄HS: I - x
<em>-Where I is an initial concentration that is not relevant for the problem and x is the </em>NH₄HS<em> that reacts-</em>
H₂S(g): x
NH₃(g): x
Replacing in (1):
0.11 = X×X
0.11 = X²
<em>0.33 = X</em>
That means P(NH₃) is <em>0.33 atm</em>
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I hope it helps!