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3 years ago

What's 4/7 times 6/7

Mathematics

2 answers:

I am Lyosha [343]3 years ago

8 0

It is 0.4 AKA 4/10 ok i do not now if i am correct
hoped i helped ;)

Goryan [66]3 years ago

6 0

The answer is: " 24/49 " .
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4/7 * 6/7 = (4*6) / (7*7) = 24/49 .
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How do I solve this ?

eduard

Look at the picture.

ΔZYX and ΔDYC are similar. Therefore the lengths of sides are in proportion:

$\dfrac{DC}{ZX}=\dfrac{DY}{ZY}$

DC = x

ZX = 16

DY = a

ZY = a + a = 2a

Substitute:

$\dfrac{x}{16}=\dfrac{a}{2a}$

$\dfrac{x}{16}=\dfrac{1}{2}$ <em>multiply both sides by 16</em>

$\boxed{x=8}$

<h3>Answer: CD = 8</h3>

6 0

4 years ago

PPPLLEEWASSSSEEE HEEELP MEE

belka [17]

For letter A the point lands on the X axis for letter B the point lands on quadrant 2 for letter C the point lands on the Y axis for number 4 the point lands on quadrant 1

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3 years ago

How would I find the domain and range of this graph?

matrenka [14]

Answer:

Domain: [-3, 5]

Range: [-5, 4]

Step-by-step explanation:

The first thing is to define what is the domain and the range. The domain of a function f (x) is the set of all the values for which the function is defined, and the range of the function is the set of all the values that f takes.

In other words, the domain is the value on the "x" axis and the range is the value on the "y" axis.

In this case, both are an interval, the domain would be from -3 to 5 and in the case of the range it would be from -5 to 4.

Domain: [-3, 5]

Range: [-5, 4]

6 0

4 years ago

john read the first 114 pages of a novel which is 3 pages less than 1/3 of the novel. write the equation

tatyana61 [14]

The equation is:

$114=\frac{p}{3}-3$

And

Total number of pages are 351

Step-by-step explanation:

The equation has to be formed by using the given information.

Let p be the total number of pages in the novel

Then

1/3rd of the p will pe:

$\frac{p}{3}$

Total pages read by John = 114

Then according to the statement

$114=\frac{p}{3}-3$

We can solve the equation to get the total pages of the novel

$114=\frac{p}{3}-3\\Adding\ 3\ on\ both\ sides\\114+3=\frac{p}{3}-3+3\\117=\frac{p}{3}\\Multiplying\ both\ sides\ by\ 3\\3*117 = \frac{p}{3}*3\\p=351$

The equation is:

$114=\frac{p}{3}-3$

And

Total number of pages are 351

Keywords: Linear equation, variable

Learn more about linear variable at:

#LearnwithBrainly

8 0

4 years ago

A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo

djverab [1.8K]

Answer:

a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) $31690.7 g/L$

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

Then we have, $R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}$ , and

$R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}$

So we obtain. $\frac{dy}{dt}=4000-\frac{2y}{25}$ , then

$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) The tank will overflow due Rin>Rout, at a rate of $80 L/min-40L/min=40L/min$ , due we have 500 L to overflow $\frac{500L}{40L/min} =\frac{25}{2} min=t$ , so we can evualuate the expression of a) $y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7$ , is the salt concentration when the tank overflows

4 0

4 years ago