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<u>Answer:</u> The theoretical yield and percent yield of is 3.93 g and 30.53 % respectively
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of = 4.00 g
Molar mass of = 238 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of to form
follows:
By Stoichiometry of the reaction:
1 mole of produces 1 mole of
So, 0.0168 moles of will produce =
of
Now, calculating the mass of from equation 1, we get:
Molar mass of = 234 g/mol
Moles of = 0.0168 moles
Putting values in equation 1, we get:
To calculate the percentage yield of , we use the equation:
Experimental yield of = 1.20 g
Theoretical yield of = 3.93 g
Putting values in above equation, we get:
Hence, the theoretical yield and percent yield of is 3.93 g and 30.53 % respectively
The given question is incomplete. The complete question is :
A chemist prepares a solution of barium acetate by measuring out 32 g of barium acetate into a 350 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's barium acetate solution. Round your answer to significant digits.
Answer: The concentration of barium acetate solution is 0.375 mol/L
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in ml
moles of =
Now put all the given values in the formula of molality, we get
Therefore, the concentration of solution is 0.375 mol/L