Answer:
Explanation:
A) Reactant that can produce more of the product
Excess reactant:
In a given reaction, the reactant that is in excess supply is the excess reactant. If the amount of the excess reactant is match, more of the product will be produced.
B) Reactant that can produce a lesser amount of the product
Limiting reactant
The limiting reactant restricts the progress of the reaction. It determines the amount of product that can be formed.
C) Amount of product predicted to be produced by the given reactants
Theoretical yield
For a given amount of reactants, the theoretical yield determines the amount of products that can be produced.
Answer:
The answer is:
(a) 
(b) NaCl
(c) 0.211 g
Explanation:
Given:
The mass of NaCl,
= 0.0860 g
The molar mass of NaCl,
= 58.44 g/mol
The volume of 
,
= 30.0 ml
or,
= 0.030 L
Molarity of ,
= 0.050 M
Moles of NaCl will be:
= 
= 
= 
now,
Moles of will be:
(a)
The reaction is:
⇒
(b)
1 mole of NaCl react with,
= 1 mol of
0.0015 mol needs,
= 
Available mol of NaCl < needed amount of NaCl
So,
The limiting reagent is "NaCl".
(c)
The precipitate formed,
= 
= 
Answer: Option (B) is the correct answer.
Explanation:
Boiling point is defined as the temperature at which vapor pressure of a liquid becomes equal to the atmospheric pressure.
Surface tension is defined as the attractive forces experienced by the surface molecules of a liquid by the molecules present beneath the surface layer of the liquid. More stronger are the intermolecular forces present within the molecules of a liquid more will be its surface tension and lower will be its vapor pressure.
Hence, higher will be the boiling point of the liquid.
And, viscosity is defined as the ability of a liquid to resist its flow. When a substance has high viscosity then it is known as a viscous substance.
Thus, we can conclude that a substance with a high boiling point will also likely have a low vapor pressure.
Answer:
Volume in L = 0.50 L
Explanation:
Given data:
Molarity of solution = 0.1850 M
Mass of BaCl₂ = 19.30 g
Volume of solution = ?
Solution:
First of all we will calculate the number of moles of solute:
Number of moles = mass/molar mass
Molar mass of BaCl₂ = 208.23 g/mol
Number of moles = 19.30 g / 208.23 g/mol
Number of moles = 0.093 mol
Volume of solution:
Molarity = number of moles of solute / volume of solution in L
0.1850 M = 0.093 mol / Volume in L
Volume in L = 0.093 mol / 0.1850 M (M= mol/L)
Volume in L = 0.50 L
Answer:
MES for pH near to 6.0 and MOPS for pH near to 7.5.
Explanation:
Hello,
In this case, given that the Henderson-Hasselbach equation is:
![pH=pKa+log(\frac{[Base]}{[Acid]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5BBase%5D%7D%7B%5BAcid%5D%7D%20%29)
Good's buffers are those having pKa's near to the required pH since we look for a [Base]/[Acid] ratio to approach 1, thus, for a pH near to 7.0 a good buffer may be MOPS as it has a pKa of 7.5 and for a pH neat to 6.0 a good buffer may be MES as it has a pKa of 6.15.
Best regards.
