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Natali5045456 [20]
4 years ago
15

What kingdom is Spirogyra in?

Chemistry
1 answer:
jasenka [17]4 years ago
8 0
Protista .................................
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(02.02 MC) Compared to ultraviolet light, an electromagnetic wave that has a higher frequency will also have ________. (4 points
erma4kov [3.2K]
Your answer would be shorter wavelength and equal speed !
3 0
3 years ago
What is a chromosome
erica [24]
A chromosome is a tightly coiled X of genetic material that has genes on it.
Hope this helps!

4 0
3 years ago
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(Help!) What is the mass of hydrogen atoms that is measured at 72 u?​
Lunna [17]

Answer:

=71.439911 u

Explanation:

We know that 1 mass of hydrogen atom = 1.00784 u

If it's measured at 72u: 72/1.00784=71.439911 u

6 0
2 years ago
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14. In the lab, an experimenter mixes 75.0 g of water (initially at 30oC) with 83.8 g of a solid metal (initially at 600oC). At
avanturin [10]

Answer:

Tungsten is used for this experiment

Explanation:

This is a Thermal - equilibrium situation. we can use the equation.

Loss of Heat of the Metal = Gain of Heat by the Water

                      -Q_{m}=+Q_{w}\\

                    Q = mΔTC_{p}

Q = heat

m = mass

ΔT = T₂ - T₁

T₂ = final temperature

T₁ = Initial temperature

Cp = Specific heat capacity

<u>Metal</u>

m = 83.8 g

T₂ = 50⁰C

T₁ = 600⁰C

Cp = x

<u>Water</u>

m = 75 g

T₂ = 50⁰C

T₁ = 30⁰C

Cp = 4.184 j.g⁻¹.⁰c⁻¹

               -Q_{m}=+Q_{w}\\

⇒ - 83.8 x x x (50 - 600) = 75 x 4.184 x (50 - 30)

⇒ x = \frac{6276}{46090} = 0.13 j.g⁻¹.⁰c⁻¹

We know specific heat capacity of Tungsten = 0.134 j.g⁻¹.⁰c⁻¹

So metal Tungsten used in this experiment

8 0
4 years ago
An unknown gas has a volume of 20L at 140K. What is its volume at STP? Be sure to show the setup and the final
kramer

Answer:

 v₂ = 39L

Explanation:

Given parameters:

Initial volume of gas  = 20L

Initial temperature  = 140K

Unknown:

Final volume  = ?

Solution:

Since the standard temperature of any gas is 273K, the final temperature is this 273K;

 Applying Charles's law:

            \frac{v_{1} }{T_{1} } = \frac{v_{2} }{T_{2} }

v and T are volume and Temperature

           \frac{20}{140}   = \frac{v_{2} }{273}  

 

         v₂ x 140  = 20 x 273

         v₂ = 39L

         

6 0
3 years ago
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