Ask question

Ask question

All categories

4 years ago

7

Which is a chacteristic of a solution?

1 answer:

Setler [38]4 years ago

8 0

Answer:

A solution is a homogeneous mixture of two or more substances. The particles of solute in a solution cannot be seen by the naked eye. A solution does not allow beams of light to scatter.

Explanation:

You might be interested in

It takes much less energy to change the temperature of oil than it does to change the temperature of water

Andrew [12]

Answer:

i think so

Explanation:

8 0

3 years ago

GenAlex Medical, a leading manufacturer of medical laboratory equipment, is designing a new automated system that can detect nor

SOVA2 [1]

Answer:

The minimum concentration of acetaminophen that can be detected by new= 10μg/mL

Volume of blood sample=2ml

Minimum mass of acetaminophen that can be detected by automated system= 10×2= 20μg= 0.020mg

6 0

3 years ago

Name two liquid fuels obtained from petroleum

Ratling [72]

Answer:

Diesel and kerosene.

Hope it helps :)

8 0

3 years ago

Read 2 more answers

The volume of 1.20 lol of gas at 61.3 kPa and 25.0 degree Celsius is

aniked [119]

Answer:

V = 48.5 L

Explanation:

Converting °C to K and kPa to atm

T = 25.0°C + 273.15 = 298.15 K

P = 61.3 kPa × (1 atm / 101.325 kPa) = 0.60498 atm

Calculating the volume of gas

V = nRT / P

V = (1.20 mol)(0.082057 L•atm/mol•K)(298.15 K) / 0.60498 atm

V = 48.5 L

4 0

3 years ago

The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma

Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C= $p_o= 187.54 mmHg$

Vapor pressure of the solution at 65 °C= $p_s$

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water= $n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol$

Moles of ethylene glycol= $n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol$

$\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}$

$\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}$

$p_s=173.83 mmHg$

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

6 0

3 years ago