Answer:
e is the answer for the question
Answer:
E°red for Tl³⁺(aq) | Tl⁺(aq) is 0.78 V
Explanation:
According to cell reaction we can predict which one cathode half cell and which one anode.
We know left hand side electrode where oxidation occur acts as an anode and right hand side electrode where reduction take place acts as an cathode.
Hence Cr²⁺ converted into Cr³⁺ since oxidation is take place where as Ti³⁺ converted into Ti⁺ means reduction take place.
<u>Anode half cell </u>is Cr³⁺(aq) | Cr²⁺(aq) is E⁰red = -0.41 V
<u>Cathode half cell</u> is Ti³⁺(aq) | Ti⁺(aq) is E⁰red = ?
E⁰cell = E⁰cathode - E⁰anode
⇒ E⁰cathode = E⁰cell + E⁰anode
⇒ E⁰cathode = 1.19 + (- 0.41) volt = 0.78 V
Answer:
0.5mol/L
Explanation:
First, let us calculate the number of mole NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH from the question = 30g
Number of mole = Mass /Molar Mass
Number of mole = 30/40 = 0.75mol
Volume = 1.5L
Active mass = mole/Volume
Active mass = 0.75mol/1.5L
Active mass = 0.5mol/L
Answer:
255.51cm3
Explanation:
Data obtained from the question include:
V1 (initial volume) =?
T1 (initial temperature) = 50°C = 50 + 273 = 323K
T2 (final temperature) = - 5°C = - 5 + 237 = 268K
V2 (final volume) = 212cm3
Using the Charles' law equation V1/T1 = V2/T2, the initial volume of the gas can be obtained as follow:
V1/T1 = V2/T2
V1/323 = 212/268
Cross multiply to express in linear form
V1 x 268 = 323 x 212
Divide both side by 268
V1 = (323 x 212)/268
V1 = 255.51cm3
Therefore, the initial volume of the gas is 255.51cm3
The answer is no because if you use the combined gas law the volume would come out to be 52.3 liters.
