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Anna007 [38]
4 years ago
13

Select the correct answer. A sealed bottle is full of air. The volume of the bottle is decreased, but the temperature remains co

nstant. What other change occurs in the bottle? A. The air pressure will increase. B. The air pressure will decrease. C. The number of air molecules will increase. D. The number of air molecules will decrease.
Chemistry
2 answers:
Sloan [31]4 years ago
8 0

Answer:

The air pressure will increase

Explanation:

The bottle is sealed, therefor the number of molecules can't change. The air inside the bottle may be considered as an ideal gas, and these have a particular set of laws they must obey.

In this case the law that apllies is Boyle's Law, which states that at a constant temperature, the pressure P of a gas varies inversely with its volume V, or P.V = k, where k is a constant.

If the volume is decreasing, the pressure must increase.

Zigmanuir [339]4 years ago
3 0
The answer would be c
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4 years ago
A sample of 5.30 mLmL of diethylether (C2H5OC2H5;density=0.7134g/mL)(C2H5OC2H5;density=0.7134g/mL) is introduced into a 6.50 L L
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Answer:

1.16atm

Explanation:

We are going to derive the mass of ether from density

mass=density *volume

Also moles=mass/molecular mass

molar mass C2H5OC2H5 =74.12 g/mole

the density of ether is 0.7134 g/ml

mass C2H5OC2H5 = 5.30 ml x 0.7134 g/ml = 3.78 g

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PV = nRT where P=?; n=0.0509 moles; V=6.50L; R=0.0821 Latm/Kmol; T=35ºC +273 = 308K

P = nRT/V = 0.0509)(0.0821)(308)/6.50

P = 0.198 atm (to 3 significant figures (this is the partial pressure of diethyl ether).  

TOTAL PRESSURE

P1+p2+p3

= 0.198 atm + 0.750 atm + 0.207 atm =1.1550atm

1.16atm(3 significant figures)

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4 years ago
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3 years ago
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A solution is prepared by mixing 0.0300 mol CH2Cl2 and 0.0500 mol CH2Br2 at 25 degrees C. Assuming the solution is ideal, calcul
Vinil7 [7]

Answer:

CH2Cl2 mole fraction =  0.833

CH2Br2 mole fraction = 0.167

Explanation:

Step 1: Data given

Number of moles CH2Cl2 = 0.0300 moles

Number of moles CH2Br2 = 0.0500 moles

Temperature = 25 °C

Vapor pressure of pure CH2Cl2 = 133 torr

Vapor pressure of pure CH2Br2 = 11.4 torr

Step 2:  Calculate mol fraction  in solution

Mol fraction CH2Cl2 = 0.0300 moles / (0.0300 + 0.0700)

Mol fraction CH2Cl2 = 0.300

Mol fraction CH2Br2 = 0.0700 moles / (0.0300 + 0.0700)

Mol fraction CH2Br2 = 0.700

Step 3: Calculate partial pressure

Partial pressure CH2Cl2 = 133 torr * 0.300 = 39.9 torr

Partial pressure CH2Br = 11.4 torr * 0.700 =7.98 torr

Step 4: Calculate the total pressure

total pressure = 39.9 + 7.98 = 47.88 torr

Step 5: Calculate mol fraction

partial pressure / total pressure = mole fraction

CH2Cl2 mole fraction = 39.9 / 47.88 = 0.833

CH2Br2 mole fraction = 7.98 / 47.88 = 0.167

3 0
3 years ago
Asap I will mark brainiest!What is the net force acting on the object in this free-body diagram? a.100 kg b.230 N c.170 N d.170
DiKsa [7]

Answer:

A..?

Explanation:

Im not entirely sure you should get a 2nd opinion M8.

8 0
3 years ago
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