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In balancing nuclear decay types of reaction, the same as balancing a chemical reaction, we use the number and the type of nucleons present for the decay reaction. Regardless of the type of decay, it should be that the total number of nucleons in the shole process should be conserved. For carbon-11, the decay equation would be as follows:
11/6 C --->11/5 B + 0/1β
It is an example of a positron emmision or a positive beta decay. It is a decay for neutron-poor nuclei where a proton is being transformed into a neutron and also emitting a positron that is high in energy.
Answer:
4NH₃ + 5O₂ → 4NO + 6H₂O ΔH = -904 kj
Explanation:
Given data:
Energy evolved when one mole of NH₃ react = 226 kj
Energy evolved when 4 mole of NH₃ react = ?
Solution:
Chemical equation:
4NH₃ + 5O₂ → 4NO + 6H₂O
It is stated in question that when one mole of ammonia react 226 kj energy evolved.
When 4 moles react energy evolved is,
1 mol = -226 kj
4 mol × -226 kj / 1mol
-904 kj
when 4 moles of ammonia react 904 kj energy is evolved.
Complete thermal equation:
4NH₃ + 5O₂ → 4NO + 6H₂O ΔH = -904 kj
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