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Anna007 [38]
4 years ago
13

Select the correct answer. A sealed bottle is full of air. The volume of the bottle is decreased, but the temperature remains co

nstant. What other change occurs in the bottle? A. The air pressure will increase. B. The air pressure will decrease. C. The number of air molecules will increase. D. The number of air molecules will decrease.
Chemistry
2 answers:
Sloan [31]4 years ago
8 0

Answer:

The air pressure will increase

Explanation:

The bottle is sealed, therefor the number of molecules can't change. The air inside the bottle may be considered as an ideal gas, and these have a particular set of laws they must obey.

In this case the law that apllies is Boyle's Law, which states that at a constant temperature, the pressure P of a gas varies inversely with its volume V, or P.V = k, where k is a constant.

If the volume is decreasing, the pressure must increase.

Zigmanuir [339]4 years ago
3 0
The answer would be c
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7 0
3 years ago
Describe an electron cloud. Then, name and explain a particular atomic model that used the concept of the electron cloud.
pochemuha

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3 0
3 years ago
What is the standard cell potential of a cell made of theoretical metals ma/ma2+ and mb/mb2+ if the reduction potentials are –0.
Yuki888 [10]
The standard cell potential of a cell made of theoretical metals ma/ma2+ and mb/mb2+ is to be determined. We are given their reduction potentials:

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6 0
3 years ago
Read 2 more answers
1.25mole Nocl was placed in a2.50l reaction chamber at 427c. After equilibrium was reached .1.10moles of Nocl remained.Calculate
Dmitry [639]

Answer:

Kc → 5.58×10⁻⁴

Explanation:

Equilibrium reaction is:

2NOCl (g) ⇄  2NO (g) + Cl₂(g)

Initially we have 1.25 moles of NOCl

After the equilibrium, we have 1.10 moles. So, during the process:

(1.25 mol - 1.1 mol) = 0.15 moles have reacted.

As ratio are 2:2, and 2:1, 0.15 moles of NO and (0.15 /2) = 0.075 moles of chlorine, were produced in the equilibrium.

Finally in equilibrium we have: 1.10 moles of NOCl, 0.15 moles of NO and 0.075 moles of Cl₂. But these amount are not molar, so we need molar concentration in order to determine Kc:

1.10 mol /2.50L = 0.44 M

0.15 mol / /2.50L = 0.06 M

0.075 mol /2.50L = 0.03 M

Let's make expression for Kc → [Cl₂] . [NO]² / [NOCl]²

Kc = (0.03 . 0.06²) / 0.44² → 5.58×10⁻⁴

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3 years ago
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Answer:

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Explanation:

3 0
3 years ago
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