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3 years ago

Is it an animal of plant cell?

Chemistry

1 answer:

Nikolay [14]3 years ago

5 0

Answer:

Structurally, plant and animal cells are very similar because they are both Eukaryotic cells. They both contain membrane-bound organelles such as the nucleus, mitochondria, endoplasmic reticulum, golgi apparatus, Iysosomes and peroxisomes. Plant cells can be larger than animal cells.

Explanation:

I majored in Chemistry

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A reaction mixture initially contains 0.140 MCO and 0.140 MH2O. What will be the equilibrium concentration of CO?

Allushta [10]

Answer:

0.013 M

Explanation:

From the question, we can make the following deductions; we are given mixture that contains two compounds, that is A and B, 0.140 M CO and 0.140 M H2O respectively. Then, we are asked to find the equilibrium concentration of Carbonmonoxide,CO.

So, the equation for the reaction is given below;

CO + H2O <-----------------> CO2 + H2.

Initially: we have 0.14M of CO, 0.14M of H2O and zero (0) concentration of CO2 and H2.

At time,t = CO =0.14 - x , H2O = 0.14 - x, CO2 and H2 = x.

The above reaction consist of the forward reaction and the backward reaction.

Therefore, the equilibrium Concentration of CO;

(Since we are giving that Kc = 102). Then, Kc= [CO2][H2] ÷ [CO][H2O]. Where Kc is the equilibrium constant.

Therefore, 102 = [x^2] / [0.14 - x]^2.

==> 10.1= x/0.14 - x.

====> 0.141 - 10.1 x = x.

x + 10.1 x = 0.141.

===> 11.1 x = 0.141.

===> x = 0.141 ÷ 11.1.

===> x = 0.127 M .

Then, at time,t CO = 0.14 - x.

= 0.14 - 0.127 = 0.013 M

8 0

3 years ago

Read 2 more answers

g Consider a uniport system where a carrier protein transports an uncharged substance A across a cell membrane. Suppose that at

Alborosie

Answer : The ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

$\Delta G^o=-RT\times \ln Q\\\\\Delta G^o=-RT\times \ln (\frac{[A]_{inside}}{[A]_{outside}})$

where,

$\Delta G^o$ = standard Gibbs free energy = -14.1 kJ/mol

R = gas constant = 8.314 J/K.mol

T = temperature = $25^oC=273+25=298K$

Q = reaction quotient

$[A]_{inside}$ = concentration inside the cell

$[A]_{outside}$ = concentration outside the cell

Now put all the given values in the above formula, we get:

$-14.1\times 10^3J/mol =-(8.314J/K.mol)\times (298K)\times \ln (\frac{[A]_{inside}}{[A]_{outside}})$

$\frac{[A]_{inside}}{[A]_{outside}}=296.2$

Thus, the ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2

3 0

3 years ago

“Aqueous calcium hydroxide reacts with carbon

bulgar [2K]

Answer:

B. Ca(OH)2(s)+CO2(aq)-CaCO3(s)+H2O(aq)

6 0

2 years ago

What does the red represent on the model? *

kaheart [24]

The red is an oxygen molecule. 1 oxygen and 2 hydrogen =h2o or water!

6 0

3 years ago

Which matter has more attraction between the particles

julia-pushkina [17]

There are spaces between particles of matter. The average amount of empty space between molecules gets progressively larger as a sample of matter moves from the solid to the liquid and gas phases. There are attractive forces between atoms/molecules, and these become stronger as the particles move closer together.

3 0

3 years ago