3 years ago

The amount of diffraction that a sound wave undergoes depends on

1 answer:

5 0

The amount of diffraction of sound waves depends on the medium the sound wave travels to and the frequency. Diffraction happens as soon as it has been out of the source.

You might be interested in

If the octupus had twelve arms then how many arms would the crab have show your work

Alexandra [31]

Answer:

I believe that the crab would have 14 arms if the octopus had 12 arms

Explanation:

4 0

2 years ago

The combination of all of the forces acting on an object is called the

Veronika [31]

The answer is Net force

6 0

3 years ago

1. What is the kinetic energy of a 94 kg basketball player running at 7.3 m/s?

LUCKY_DIMON [66]

1. 2504.63 J

2. 929.5m/s

Hope this helps :)

I can explain it as well if you’d like

8 0

3 years ago

The phenomenon of vehicle "tripping" is investigated here. The sport-utility vehicle is sliding sideways with speed v1 and no an

Mrrafil [7]

Answer:

$v_1 = 3.5 \ m/s$

Explanation:

Given that :

mass of the SUV is = 2140 kg

moment of inertia about G , i.e $I_G$ = 875 kg.m²

We know from the conservation of angular momentum that:

$H_1= H_2$

$mv_1 *0.765 = [I+m(0.765^2+0.895^2)] \omega_2$

$2140v_1*0.765 = [875+2140(0.765^2+0.895^2)] \omega_2$

$1637.1 v_1$ $= 3841.575 \omega_2$

$\omega_2 = \frac{1637.1 v_1}{3841.575}$

$\omega _2 = 0.4626 \ v_1$

From the conservation of energy as well;we have :

$T_2 +V_{2 \to 3} = T_3 \\ \\ \\ \frac{1}{2} I_A \omega_2^2 - mgh =0$

$[\frac{1}{2} [875+2140(0.765^2+0.895^2)](0.4262 \ v_1)^2 -2140(9.81)[\sqrt{0.76^2+0.895^2} -0.765]] =0$

$706.93 \ v_1^2 - 8657.49 =0$

$706.93 \ v_1^2 = 8657.49$

$v_1^2 = \frac{8657.49}{706.93 }$

$v_1 ^2 = 12.25$

$v_1 = \sqrt{ 12.25$

$v_1 = 3.5 \ m/s$

6 0

3 years ago

What is the momentum of a 0.1-kg mass moving with a speed of 5 m/s

Andrej [43]

This question is wrong because in momontum we will write acceleration instead of speed. suppose acceleration is 5m/s2 then
P= ma
then put values

4 0

3 years ago