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3 years ago

8

The ____ of an objects is give relative ro an origin

1 answer:

leva [86]3 years ago

3 0

The position of an object is given relative to an origin.

'Origin' here simply means a standard point of reference. For example, when we plan to go to a supermarket in our locality, we think of how many streets or blocks away that place is from our house. Here our house serves as the origin about which we locate the position of several stores.

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lianna [129]

Answer:

13671

Explanation:

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2 years ago

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A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.

stira [4]

Answer:

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3 years ago

Complete the sentence with the word "element" or "compound." O is a(n) and H202 is a(n)

Sauron [17]

Answer:

O is an element and H2O2 is a compound.

Explanation:

O is a single element while H2O2 has 2 elements, which makes it a compound.

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3 years ago

Luke Autbeloe drops an approximately 5.0 kg object (weight = 50.0 N) off the roof of his house into the swimming pool below. Upo

Murljashka [212]

Answer:

Graph B represents correct graph for velocity time

Explanation:

Initially the object is dropped under the influence of constant force due to gravity

So here we can say its acceleration is constant due to gravity

hence here the velocity will increase downwards due to gravity and it is given as

$v = 0 + (-10)t$

now when it enters into the pool an upward force of same magnitude will act on it

so net force on it is

$F = 50 - 50 = 0$

so here we will have no acceleration and it will move with constant speed after that

so here correct graph is

Graph B

6 0

4 years ago

A golf ball has a mass of 120g. Calculate its increase in mass when it is travelling at 40ms1. What is this as a percentage of i

kicyunya [14]

Answer:

$Percentage=8.889\times 10^{-13}$ %

Explanation:

From special theory of relativity the dynamic mass m is related with the rest mass $m_{0}$ of the body as

$m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }$

Here, c is the speed of light and v is the velocity of object.

Given mass of the golf ball is 120 g.

$m=\frac{120 }{\sqrt{1-\frac{(40)^{2} }{(3\times 10^{8} )^{2} } } }\\m=120(1-\frac{(40)^{2} }{(3\times 10^{8}) ^{2} })^{-\frac{1}{2} } \\$

Now applying the binomial theorem and solve the above equation.

$m=(1+\frac{1}{2}(\frac{40}{3\times 10^{8} }) ^{2} )\\m=120(1+8.889\times 10^{-15})$

Therefore, increase in mass is,

$\Delta m=120\times 8.889\times 10^{-15} \\\Delta m=10.6668\times 10^{-13} g$

Now percentage of increase in mass with rest mass is,

$Percentage=\frac{10.6668\times 10^{-13} g}{120g} \times 100\\Percentage=8.889\times 10^{-13}$

Therefore, the percentage of increase in mass with rest mass is $Percentage=8.889\times 10^{-13}$ .

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4 years ago