In experiment 1, how many moles of benzoic acid are present? how many moles of sodium bicarbonate are contained in 1 ml of a 10%

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In experiment 1, how many moles of benzoic acid are present? how many moles of sodium bicarbonate are contained in 1 ml of a 10%

aqueous solution? (a 10% solution has 1 g of solute in 9 ml of solvent.) is the amount of sodium bicarbonate sufficient to react with all of the benzoic acid?

Chemistry

1 answer:

nexus9112 [7] · Answer 1 · 2022-02-13T15:34:07+03:00

First, let us calculate the moles of solute or sodium bicarbonate is in the 1 ml solution.

<span>moles = 1 mL * (1 g / 9 mL) = 0.11 moles</span>

The molar mass of sodium bicarbonate is 84 g/mol, therefore the mass is:

mass = 0.11 moles * 84 g/mol