(9) A penny contains 22,452,000,000,000,000,000,000 zinc atoms and also contains

¿Qué volumen ocuparán 12 g de hierro?

sasho [114]

Answer:

$\large\boxed{\large\boxed{volume=1.5cm^3}}$

Explanation:

Translation:

What volume will 12g of iron occupy?

<h2>Solution</h2>

Iron is a solid substance at room temperature. You can find the volume of solids (and of not solids) using the density.

$Density=\dfrac{mass}{volume}$

You can obtaindthe density of most pure substances in the internet. The density of iron at room temperature is 7.874 g/cm³.

Thus, substituting in the formula, you get:

$7.874g/cm^3=\dfrac{12g}{volume}\\ \\ \\ volume=\dfrac{12g}{7.874g/cm^3}\\ \\ \\ volume=1.5cm^3$

The answer is rounded to two significant figures because the input, 12g, has two significant figures.

8 0

3 years ago

1. A container holds four times as many moles of CO2 as O2. If the total pressure in the container is 20. atm,

Hitman42 [59]

Answer:

Partial pressure of CO2 = 16 atm

Explanation:

Total number of moles of gases = 4+1 = 5 moles

Mole fraction of CO2 = 4/5

Partial pressure of CO2 = mole fraction of CO2 × total pressure

Partial pressure of CO2 = (4/5) × 20

Partial pressure of CO2 = 16 atm

7 0

3 years ago

What volume would 75.0g of oxygen gas occupy

seropon [69]

Answer:

Explanation: It is already known that 1 mole of the gas( or 32g of O2) is equivalent to 22.4 Litres of the oxygen gas. So, 8g is equivalent to = (22.4/32) × 8 = 5.6 L of the gas.

7 0

3 years ago

Please help mee!!!!

GREYUIT [131]

The meaning of observations to see small touch

6 0

2 years ago

Combustion of hydrocarbons such as nonane () produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosp

maksim [4K]

Answer:

Part 1: C₉H₂₀ (l) + 14O₂ (g) ----> 9CO₂ (g) + 10H₂0 (g)

Part 2: Volume of CO₂ produced = 1223.21 L

Note: the complete second part of the question is given below:

2. Suppose 0.470 kg of nonane are burned in air at a pressure of exactly 1 atm and a temperature of 17.0 °C. Calculate the volume of carbon dioxide gas that is produced. Round your answer to 3 significant digits.

Explanation:

Part 1: Balanced chemical equation

C₉H₂₀ (l) + 14O₂ (g) ----> 9CO₂ (g) + 10H₂0 (g)

Part 2: volume of carbon dioxide produced

From the equation of the reaction;

At s.t.p., I mole of C₉H₂₀ reacts with 14 moles of O₂ to produce 9 moles of CO₂

molar mass of C₉H₂₀ = 128g/mol: molar mass of CO₂ = 44 g/mol, molar volume of gas at s.t.p. = 22.4 L

Therefore, 128 g of C₉H₂₀ produces 14 * 22.4 L of CO₂ i.e. 313.6 L of CO₂.

O.470 Kg of nonane = 470 g of nonane

470 g of C₉H₂₀ will produce 470 * (313.6/128) L of CO₂ = 1151.50 L of CO₂

Volume of CO₂ gas produced at 1 atm and 17 °C;

Using P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/P₂T₁

where P₁ = 1 atm, V₁ = 1151.50 L, T₁ = 273 K, P₂ = 1 atm, T₂ = 17 + 273 = 290 K

Substituting the values; V₂ = (1 * 1151.5 * 290)/(1 * 273)

Therefore volume of CO₂ produced, V₂ = 1223.21 L of CO₂

3 0

3 years ago