A. 2.9384 x -7
B. 9.0832 x 9
C. 3.4455 x -3
D. 2 x 3
Answer:
Explanation:
Hello there!
In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:
Thus, we solve for the molarity of the acid to obtain:
Regards!
The boiling point increase of a solution is a colligative property, which means that it is related with the solvent and the concentration of the solute, as per this formula:
ΔT = i * kb * m
Where, ΔT is the increase in the boiling point, i is the van't Hoof factor (which accounts for the numberof particles that are dissolved), kb is the boiling point and m the molality of the solution.
Gvien the normal boiling point of 100°C for pure water, ΔT = 101.4 °C - 100.0 °C = 1.4 °C.
Kb = 0.512 °C / m
m = 1.2 m
Therefore, i = ΔT / (kb * m) = 1.4°C / (0.512 °C/m * 1.2m) = 2.28
Answer: 2.28
Answer:
This reaction can be expressed as a word equation: copper + silver nitrate → silver + copper nitrate You can replace each part of the word equation by a chemical formula: Cu + AgNO3 → Ag + Cu(NO3)2 Looking at both sides of this equation, you can see that it is not balanced.