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VMariaS [17]
2 years ago
13

which statement is true about the part of the electromagnetic spectrum that is visible to the human eye?

Chemistry
2 answers:
IgorLugansk [536]2 years ago
6 0
Hello @Lucysrv18,

How are you doing? In this case, we know that Electromagnetic waves that are visible to the human eye is neither made up of two electromagnetic waves nor three. Therefore B and C is incorrect.

These electromagnetic waves are divided and they are our final two options. For sure, i can say that the wavelengths in a visible electromagnetic wave are not divided into nine, but instead it is divided into 7. 

The answer to your question is A. 

Thank you,
Darian D. 

mezya [45]2 years ago
5 0

Answer: a

i JUST TOOK THE TEST

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<h3>Further explanation</h3>

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\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793

So  FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

\tt \dfrac{6}{3}\times 0.714=1.428

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