A bird flies at a speed of 2.3 m/s if it has 14 j of kinetic energy what is the mass
2 answers:
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Question #1:
a). The sketch is attached to this answer.
b). The equivalent resistance of 30Ω and 50Ω in parallel is
1 / (1/30 + 1/50) = 18.75 Ω
c). I = V/R = (100/30) = (3 and 1/3) Amperes
d). Follow the wires, and you see that the 50Ω resistor is
connected directly to the battery, and so is the voltmeter.
So the voltage across the 50Ω resistor, and the reading
on the voltmeter, is 100 volts.
e). I = V/R
Through the 30Ω resistor: I = 3-1/3 A
Through the 50Ω resistor: I = 2 A
f). In the parallel circuit, both resistors are connected
directly to the battery. So neither resistor even knows
that the other one is there. Each resistor sees 100 volts,
and the current through each resistor is 100/R, just as if
it were the only resistor in the circuit.
a). The sketch is attached to this answer.
b). The equivalent resistance of 30Ω and 50Ω in parallel is
1 / (1/30 + 1/50) = 18.75 Ω
c). I = V/R = (100/30) = (3 and 1/3) Amperes
d). Follow the wires, and you see that the 50Ω resistor is
connected directly to the battery, and so is the voltmeter.
So the voltage across the 50Ω resistor, and the reading
on the voltmeter, is 100 volts.
e). I = V/R
Through the 30Ω resistor: I = 3-1/3 A
Through the 50Ω resistor: I = 2 A
f). In the parallel circuit, both resistors are connected
directly to the battery. So neither resistor even knows
that the other one is there. Each resistor sees 100 volts,
and the current through each resistor is 100/R, just as if
it were the only resistor in the circuit.
Answer:
Tension= (g=acceleration of gravity)
Explanation:
Given that,
A 5Kg and 10Kg are attached by a cable suspended over a pulley.
As 10Kg > 5Kg , the 10 kg mass accelerates down and the 5kg mass accelerates up, let it be a. Let the tension in the cable be T.
So, the equations of motion are
Now adding them we get,
Substituting them back in the equation we get,