Answer:
h = 1.8 m
Explanation:
The initial velocity of the glove, u =- 6 m/s
We need to find the maximum height of the glove. Let it is equal to h. Using equation of kinematics. At the maximum height v = 0
, h is the maximum height and a = -g
![0^2-(6)^2=2\times (-10)\times h\\\\h=\dfrac{36}{20}\\\\h=1.8\ m](https://tex.z-dn.net/?f=0%5E2-%286%29%5E2%3D2%5Ctimes%20%28-10%29%5Ctimes%20h%5C%5C%5C%5Ch%3D%5Cdfrac%7B36%7D%7B20%7D%5C%5C%5C%5Ch%3D1.8%5C%20m)
Hence, it will go up to a height of 1.8 m.
Answer:
E = 58.7 V/m
Explanation:
As we know that flux linked with the coil is given as
![\phi = NBA](https://tex.z-dn.net/?f=%5Cphi%20%3D%20NBA)
here we have
![A = \pi R_s^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cpi%20R_s%5E2)
![B = \mu_o N i/L](https://tex.z-dn.net/?f=B%20%3D%20%5Cmu_o%20N%20i%2FL)
now we have
![\phi = N(\mu_o N i/L)(\pi R_s^2)](https://tex.z-dn.net/?f=%5Cphi%20%3D%20N%28%5Cmu_o%20N%20i%2FL%29%28%5Cpi%20R_s%5E2%29)
now the induced EMF is rate of change in magnetic flux
![EMF = \frac{d\phi}{dt} = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L](https://tex.z-dn.net/?f=EMF%20%3D%20%5Cfrac%7Bd%5Cphi%7D%7Bdt%7D%20%3D%20%5Cmu_o%20N%5E2%20%5Cpi%20R_s%5E2%20%5Cfrac%7Bdi%7D%7Bdt%7D%2FL)
now for induced electric field in the coil is linked with the EMF as
![\int E. dL = EMF](https://tex.z-dn.net/?f=%5Cint%20E.%20dL%20%3D%20EMF)
![E(2\pi r_c) = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L](https://tex.z-dn.net/?f=E%282%5Cpi%20r_c%29%20%3D%20%5Cmu_o%20N%5E2%20%5Cpi%20R_s%5E2%20%5Cfrac%7Bdi%7D%7Bdt%7D%2FL)
![E = \frac{\mu_o N^2 R_s^2 \frac{di}{dt}}{2 r_c L}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5Cmu_o%20N%5E2%20R_s%5E2%20%5Cfrac%7Bdi%7D%7Bdt%7D%7D%7B2%20r_c%20L%7D)
![E = \frac{(4\pi \times 10^{-7})(6500^2)(0.14^2)(79)}{2(0.20)(3.50)}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%284%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%29%286500%5E2%29%280.14%5E2%29%2879%29%7D%7B2%280.20%29%283.50%29%7D)
![E = 58.7 V/m](https://tex.z-dn.net/?f=E%20%3D%2058.7%20V%2Fm)
The total quantity of electrons that have flowed through a circuit is a
quantity of charge, measured in Coulombs, or in Ampere-seconds.
The <em><u>rate</u></em> of flow of electrons, or more accurately the rate of flow of
the charge on them, is electrical current. Its unit is the Ampere.
1 Ampere is 1 Coulomb of charge per second.
Answer:
F.
Explanation:
Here in the question the mass of the pulley is zero, hence, the tension in the cable throughout is same.
magnitude of tension in rope 1 is
T1= F
Hence the tension T1 is rope 1 is F.
D.
The reading between 7N and 8N would have to be 7.5N. Answers A and B are much to small and answer C is way to big.