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zalisa [80]
3 years ago
10

8. What is the S.l unit for mass? A. kg B. m/s2 D.N C. m/s

Physics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

the answer is kg

Explanation:

because the s.i unit for mass is kilogram

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The length of the adult mosquito is typically between 3.0 mm and 6.0 mm. The smallest known mosquitoes are around 2.5 mm, and th
FrozenT [24]

0.74in

Explanation:

Given parameters:

length range of adult mosquito = 3.0 - 6.0mm

Smallest mosquito = 2.5mm

Largest mosquito = 19mm

Average mass range = 3.0 - 5.0mg

Unknown:

Length of largest known mosquito in inches = ?

Solution;

The length is the longest dimension. It is how long a body is.

 The problem here is converting from mm to inches;

 

The length of the longest mosquito which is the largest is 19mm

 19mm to inches;

     1mm = 0.039inches

  19mm = 19mm x \frac{0.039in}{1mm} = 0.74in

learn more:

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3 years ago
What is the us specification for ac power?
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120 volts for most home a phone charger can convert 120 volts ac to 5 volts dc
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3 years ago
Why can't there be a number lower than absolute zero
nexus9112 [7]

Absolute zero is not about numbers.  It's about temperature, and the
motion of molecules in gases. 

You know that the temperature we feel with our skin is the result of the
average speed of all the tiny molecules zipping around or vibrating in
the solid, liquid, or gas.

The faster they're all moving, the warmer the substance feels to us. 
The slower they're all moving, the cooler the substance feels to us.

When molecules slow down to zero and lose all of their kinetic energy,
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5 0
3 years ago
Read 2 more answers
You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N while the opposing force of
Rzqust [24]

Answer:

<h2>3.36J</h2>

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

                                       = 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

<u>Therefore the work of the 1.55N 3.36J</u>

4 0
2 years ago
What does the magnitude of centripetal acceleration depend on ?
MariettaO [177]

Explanation:

Centripetal acceleration ac is the acceleration experienced while in uniform circular motion. It always points toward the center of rotation. It is perpendicular to the linear velocity v and has the magnitude ac=v2r;ac=rω2 a c = v 2 r ; a c = r ω 2 .

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3 years ago
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