Answer:
Explanation:
Range of projectile R = 20 m
formula of range
R = u² sin2θ / g
u is initial velocity , θ is angle of projectile
putting the values
20 = u² sin2x 40 / 9.8
u² = 199
u = 14.10 m /s
At the initial point
vertical component of u
= u sin40 = 14.1 x sin 40
= 9.06 m/s
Horizontal component
= u cos 30
At the final point where the ball strikes the ground after falling , its speed remains the same as that in the beginning .
Horizontal component of velocity
u cos 30
Vertical component
= - u sin 30
= - 9.06 m /s
So its horizontal component remains unchanged .
change in vertical component = 9.06 - ( - 9.06 )
= 18.12 m /s
change in momentum
mass x change in velocity
= .050 x 18.12
= .906 N.s
Impulse = change in momentum
= .906 N.s .
Answer:
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We begin by noting that the angle of incidence is the one that's taken with respect to the normal to the surface in question. In this case the angle of incidence is 30. The material is Flint Glass according to the original question. The refractive indez of air n1=1, the refractive index of red in flint glass is nred=1.57, finally for violet in the glass medium is nviolet=1.60. Snell's Law dictates:
![n_1sin(\theta_1)=n_2sin(\theta_2)](https://tex.z-dn.net/?f=n_1sin%28%5Ctheta_1%29%3Dn_2sin%28%5Ctheta_2%29)
Where
![\theta_2](https://tex.z-dn.net/?f=%5Ctheta_2)
differs for each wavelenght, that means violet and red will have different refractive indices in the glass.
In the second figure provided details are given on which are the angles in question,
![\Delta x](https://tex.z-dn.net/?f=%5CDelta%20x%20)
is the distance between both rays.
![\theta_{2red}=Asin(\frac{sin(30)}{1.57})\approx 18.5705](https://tex.z-dn.net/?f=%5Ctheta_%7B2red%7D%3DAsin%28%5Cfrac%7Bsin%2830%29%7D%7B1.57%7D%29%5Capprox%2018.5705)
![\theta_{2violet}=Asin(\frac{sin(30)}{1.60})\approx 18.21](https://tex.z-dn.net/?f=%5Ctheta_%7B2violet%7D%3DAsin%28%5Cfrac%7Bsin%2830%29%7D%7B1.60%7D%29%5Capprox%2018.21)
At what distance d from the incidence normal will the beams land at the bottom?
For violet we have:
![d_{violet}=h.tan(\theta_{2violet})\approx 0.0132m](https://tex.z-dn.net/?f=d_%7Bviolet%7D%3Dh.tan%28%5Ctheta_%7B2violet%7D%29%5Capprox%200.0132m)
For red we have:
![d_{red}=h.tan(\theta_{2red})\approx 0.0134m](https://tex.z-dn.net/?f=d_%7Bred%7D%3Dh.tan%28%5Ctheta_%7B2red%7D%29%5Capprox%200.0134m)
We finally have:
Answer:
A light beam incident on a diffraction grating consists of waves with two different wavelengths. The separation of the two first order lines is great if
the dispersion is great
Answer: From space/ astronauts
Explanation:
A black hole is a place in space where gravity pulls so much that even light can not get out. The gravity is so strong because matter has been squeezed into a tiny space. This can happen when a star is dying.
Because no light can get out, people can't see black holes. They are invisible. Space telescopes with special tools can help find black holes. The special tools can see how stars that are very close to black holes act differently than other stars.