The equilibrium constant is 1.3 considering the reaction as written in the question.
<h3>Equilibrium in chemical reactions</h3>
In a chemical reaction, the equilibrium constant is calculated based on the equilibrium concentration of each specie. The equation of this reaction is;
A (g) + 2B (g) ⇌ 3C (g).
The initial concentration of each specie is;
- A - 9.22 M
- B - 10.11 M
- C - 27.83 M
The equilibrium concentration of B is 18.32 M
We now have to set up the ICE table as follows;
A (g) + 2B (g) ⇌ 3C (g)
I 9.22 10.11 27.83
C -x -x +x
E 9.22 - x 10.11 - x 27.83 + x
The equilibrium concentration of B is 18.32 M hence;
10.11 - x = 18.32
x = 10.11 - 18.32 = -8.21
Hence;
Equilibrium concentration of A = 9.22 - (-8.21) = 17.43
Equilibrium concentration of C = 27.83 + (-8.21) = 19.62
Equilibrium constant K = [19.62]^3/[17.43] [18.32]^2
K = 1.3
Learn more about equilibrium constant: brainly.com/question/17960050
<span>a thermodynamic quantity representing the unavailability of a system's thermal energy for conversion into mechanical work, often interpreted as the degree of disorder or randomness in the system.</span>
Alcohol in water is correctly termed "miscible". The equivalent answer is B.
If this has helped you, consider my answer to become the Brainliest!
One box is 120g.
mass of 126 boxes = 126*120 = 15120 g
(note: used an additional significant figure when first digit is a 1, so four significant figures)
Using the conversion 1 lb. = 453.6 g/lb
15120g = 15120 g / (453.6 g/lb) = 15120 g * (1/453.6) lb/g = 33.3 lbs. (3 significant figures)
