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Artemon [7]
1 year ago
9

What would happen to the oxygen atoms in ozone if the ozone layer were completely destroyed by ultraviolet radiation?

Chemistry
1 answer:
ale4655 [162]1 year ago
5 0

When the oxygen atoms in ozone layer were destroyed by ultraviolet radiations the individual oxygen atoms will make bond with each other and form paired oxygen molecules again to form ozone.

What is the ozone layer?

Ozone layer has a high concentration of ozone (O3) in comparison to the rest of the atmosphere, although it is still low in comparison to other gases in the stratosphere.

The ozone layer contains less than ten parts per million of ozone, whereas the normal ozone concentration in the Earth's atmosphere is around 0.3 parts per million. The ozone layer is mostly found in the lower stratosphere.

To learn more about ozone layer click the given link

brainly.com/question/1449495

#SPJ4

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Can a window pane be considered a mineral?
hichkok12 [17]

Answer:

Explanation:

The glass (which does not crystallize even though it is accepted) of a window is NOT a mineral, since it is neither a substance of natural origin (although it is manufactured from natural components) nor does it have a defined crystalline structure, that is, the atoms they are not arranged in an orderly and regular way along axes and planes forming flat faces that keep a symmetry.

Remember that a mineral is defined as a solid, inorganic, homogeneous substance, of natural origin, with a crystalline structure and a determined and well-defined chemical composition within narrow margins and that has regular and characteristic physical properties.

8 0
3 years ago
Read 2 more answers
Determine the identity of a cube of metal that measures 1.2 cm on each side and has a mass of 15.4g.
FromTheMoon [43]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
density 15.4 grams per 1.2³ cm³ ≅ 8.9 grams per cm³ 
<span>Find the metal that has a density of approximately 8.9 g/cm³</span>
8 0
2 years ago
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A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? A
anygoal [31]

this is a dilution equation where 50.0 mL of 1.50 M H₂SO₄ is taken and added to 200 mL of water.

c1v1 = c2v2

where c1 is concentration and v1 is volume of the concentrated solution

and c2 is concentration and v2 is volume of the diluted solution to be prepared

50.0 mL of 1.50 M H₂SO₄ is added to 200 mL of water so the final solution volume is - 200 + 50.0 = 250 mL

substituting these values in the formula

1.50 M x 50.0 mL = C x 250 mL

C = 0.300 M

concentration of the final solution is A) 0.300 M

4 0
3 years ago
Read 2 more answers
Tron 200g dung dich NaCl 40% voi m gam dung dich NaCl 20% thu duoc dung dich NaCl 25% . tinh m
Sati [7]

Answer:cool

Explanation:radical dude

8 0
2 years ago
Please help, I really don’t understand this!!!
kap26 [50]

<u>Analysing the Question:</u>

We are given the balanced equation:

C₆H₁₂O₆ + 6O₂→ 6CO₂ + 6H₂O

from this equation, we can say that: <em>for every 1 mole of Glucose, we need 6 moles of Oxygen</em>

<u>Moles of Glucose used in the reaction:</u>

Molar mass of Glucose = 180 grams / mol

Given mass of Glucose = 1 gram

Mole of Glucose = Given mass / Molar mass

Moles of Glucose = 1 / 180 moles

<u>Mass of Oxygen required:</u>

We know that for every mole of Glucose, we need 6 moles of Oxygen

So, for 1/180 moles of Glucose, we need 6 / 180 = 1 / 30 moles of Oxygen

Mass of 1 / 30 moles of Oxygen:

Mass = Molar mass * number of moles

Mass of Oxygen = 32 * 1/30

Mass of Oxygen  = 32 / 30

Mass of Oxygen = 1.06 grams

5 0
3 years ago
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