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3 years ago

If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?

Chemistry

1 answer:

Aleonysh [2.5K]3 years ago

8 0

Answer:

34.3 g NH3

Explanation:

M(H2) = 2*1 = 2 g/mol

M(N2) = 2*14 = 28 g/mol

M(NH3) = 14 + 3*1 = 17 g/mol

23.6 g H2* 1 mol/2 g = 11.8 mol H2

28.3 g N2 * 1 mol/28 g = 1.01 mol N2

3H2 + N2 ------> 2NH3

from reaction 3 mol 1 mol

given 11.8 mol 1.01 mol

We can see that H2 is given in excess, N2 is limiting reactant.

3H2 + N2 ------> 2NH3

from reaction 1 mol 2 mol

given 1.01 mol x

x = 2*1.01/1= 2.02 mol NH3

2.02 mol * 17g/1 mol ≈ 34.3 g NH3

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