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3 years ago

What does x equal In this equation?

Mathematics

1 answer:

Oliga [24]3 years ago

6 0

$\frac{x}{15} = \frac{4}{5} \\ Change\ both\ fractions\ to\ a \\ common\ denominator, \\ \\ \frac{x}{15} = \frac{4 \times 3}{5 \times 3} \\ \frac{x}{15} = \frac{12}{15} \\ x = 12$

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3 years ago

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Vaselesa [24]

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Step-by-step explanation:

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3 years ago

Eliza is a chef at a restaurant. she is making spaghetti sauce and put 21 tomatoes and 6 onions in the pot. what is the ratio of

seraphim [82]

These are not hard....u just have to pay very close attention to the wording. Keep in mind ratios can be written as fractions too.

ratio of tomatoes to onions = 21:6 which reduces to 7:2...because there is 21 tomatoes and 6 onions. (21/6 reduces to 7/2...ratios written as fractions)

However, if it would have asked the ratio of onions to tomatoes, it would have been 6:21....which reduces to 2:7....so pay attention to the wording on problems such as these

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3 years ago

The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard

arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ $1^s^t$ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have: $\mu=5\ ft$ $\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1$

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒ $2^n^d$ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1$

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒ $3^r^d$ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2$

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒ $4^t^h$ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3$

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

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3 years ago

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SpyIntel [72]

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