Answer:
6=k
Step-by-step explanation:
 
        
             
        
        
        
These are not hard....u just have to pay very close attention to the wording. Keep in mind ratios can be written as fractions too.
ratio of tomatoes to onions = 21:6 which reduces to 7:2...because there is 21 tomatoes and 6 onions. (21/6 reduces to 7/2...ratios written as fractions)
However, if it would have asked the ratio of onions to tomatoes, it would have been 6:21....which reduces to 2:7....so pay attention to the wording on problems such as these
so ur answer is 7:2
        
             
        
        
        
Answer:
A tree with a height of 6.2 ft is 3 standard deviations above the mean
Step-by-step explanation:
⇒  statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)
 statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)
an X value is found Z standard deviations from the mean mu if:

In this case we have:  

We have four different values of X and we must calculate the Z-score for each
For X =5.4\ ft

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.
⇒ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean.
(FALSE)
 statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean.
(FALSE)
For X =4.6 ft  

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean
.
⇒ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean
(FALSE)
 statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean
(FALSE)
For X =5.8 ft

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.
⇒ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean.
(TRUE)
 statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean.
(TRUE)
For X =6.2\ ft

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.
 
        
             
        
        
        
The exponential growth in biology is A=Pert, where "A" is the ending amount of whatever you're dealing with , "P" is the beginning amount of that same "whatever", "r" is the growth or decay rate, and "t" is time. The formula is related to the compound-interest formula, and represents the case of the interest being "compounded continuously".