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3 years ago

This problem has been solved!

Physics

1 answer:

Liono4ka [1.6K]3 years ago

3 0

Answer:

Explanation:

In this problem we can use Bohr's atomic model, to deal with the electronic transition, so we can have transitions between two given states.

ΔE = $E_{f}$ -E₀

Lower state final state energy

Fundamental first excited state ΔE₁ = -2.4 - (-4.7) = 2.3 eV

Fundamental second excited state ΔE₂ = -1.0 - (-4.7) = 3.7 eV

Fundamental third excited state ΔE₃ = -0.3 - (-4.7) = 4.4 eV

As they indicate that there are no electrons in the excited states these are the only possible transitions.

When a wide range of light strikes, the frequencies of these energies are absorbed and observed as black bands (absence of radiation) in the spectrum.

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While helping an astronomy professor, you discover a binary star system in which the two stars are in circular orbits about the

svetoff [14.1K]

Answer:

The value is $d = 3.66 *10^{10} \ m$

Explanation:

From the question we are told that

The orbital period is $T = 31.3 \ days = 31.3 * 86400 = 2704320 \ s$

Generally for the centripetal force acting one of the stars will be equal to the gravitational force between the stars and this can be mathematically represented as

$F_g = F_c$

=> $\frac{Gm*m}{d^2} = \frac{mv^2}{r}$

Here m represents the mass of each star given that they have same mass and this equal to the mass of the sun whose value is

$m = 1.989*10^{30} \ kg$

d(2 * r) is the diameter of the orbit which is distance between each star

r is the radius of the orbit

G is the gravitational constant with value $G= 6.67*0^{-11} \ m^2/kg \cdot s^2$

v is the velocity of the stars which can be mathematically represented as

$v = \frac{2 \pi r}{T}$

$\frac{Gmm }{(2 * r)^2} = \frac{m (\frac{2\pi r}{T} )^2}{r}$

=> $r =[ \frac{Gm T^2}{16 \pi ^2} ]^{\frac{1}{3} }$

=> $r = [\frac{6.67 *10^{-11} * (1.989 *10^{30}) * 2704320^2}{16 * (3.142)^2} ]^{\frac{1}{3} }$

=> $r = 1.83 *10^{10} \ m$

Generally the distance between the star is

$d = 2 * r$

=> $d = 2 * 1.83 *10^{10}$

=> $d = 3.66 *10^{10} \ m$

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3 years ago

What potential difference vwc between the wire and the cylinder produces an electric field of 2.00Ã104 volts per meter at a dist

vovikov84 [41]

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4 years ago

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Assoli18 [71]

Answer:

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Explanation:

The reason why the boy has a greater momentum is because the truck is at rest so it isn’t moving and momentum has to do with the quantity of motion

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