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lesya [120]
3 years ago
8

Chris, Mary Beth, and Allison sat discussing the number of oranges are grown in Florida. Chris says that approximately 14.6% of

the world's oranges are grown in Florida, Mary Beth says that 292 out of 2000 oranges are grown in Florida, and Allison says that 0.146 of the oranges are grown in Florida. Are they in a agreement? Explain your reasoning.
Mathematics
1 answer:
Bumek [7]3 years ago
7 0
They are in agreement. All of the expressions provided are equivalent. Chris says that 14.6 percent of the world's oranges are grown in Florida. Then, Mary Beth says that 292 out of 2000 oranges are grown in Florida. If we compare the two, 292 is actually 14.6 percent of 2000. So they are saying the same thing. Allison says that 0.146 of the oranges are grown in Florida. 0.146 is actually 14.6 percent as a decimal, so if we change it back into a percent, she is saying that 14.6 percent of oranges are grown in Florida. Sound familiar? They are all in agreement.<span />
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Jeff took his son to Great Clips to get his hair cut. His hair cut cost $9 with tax
agasfer [191]

Answer:

$10.80

Step-by-step explanation:

That’s the answer

5 0
3 years ago
Given that Ray B A bisects ∠DBC, which statement must be true? m∠ABD = m∠ABC AB ≅ BC B is the midpoint of DC. m∠DBC = 90°
nadya68 [22]

Answer:

A.m\angle ABD=m\angle ABC

Step-by-step explanation:

We are given that a  ray BA bisects angle DBC.

We have to find true statement .

Angle bisector property:When a ray bisect any angle then the angles  made by bisection of angle are equal.

When ray BA bisects angle DBC

Then, m\angle ABD=m\angle ABC

By angle bisector property.

Therefore, option A is true.

Answer:A.m\angle ABD=m\angle ABC

4 0
3 years ago
Read 2 more answers
Integration: How would I get to this answer?
Scrat [10]
Given that y attains a maximum at x=1, it follows that y'=0 at that same point. So integrating once gives

\displaystyle\int\frac{\mathrm d^2y}{\mathrm dx^2}\,\mathrm dx=\int-8x\,\mathrm dx
\dfrac{\mathrm dy}{\mathrm dx}=-4x^2+C_1
\implies -4(1)^2+C_1=0\implies C_1=4

and so the first derivative is y'=-4x^2+4.

Integrating again, you get

\displaystyle\int\frac{\mathrm dy}{\mathrm dx}\,\mathrm dx=\int(-4x^2+4)\,\mathrm dx
y=-\dfrac43x^3+4x+C_2

You know that this curve passes through the point (2, -1), which means when x=2, you have y=-1:

-1=-\dfrac43(2)^3+4(2)+C_2
\implies C_2=\dfrac53

and so

y=-\dfrac43x^3+4x+\dfrac53
7 0
4 years ago
A 22 gram sample of substance that's used to surgical instruments has k-value of 0.138
stiks02 [169]
Yeah thats right y u pretty much asked a true or false question 
8 0
4 years ago
Plz help! ASAP! What is the expression shown below
astra-53 [7]

we are given

\frac{1}{2} (\frac{3}{2} x+6x+1)-3x

step-1: Simplify expression inside parenthesis

we will combine like terms

so, firstly we will take common denominator

\frac{1}{2} (\frac{3}{2} x+\frac{2*6}{1*2}x+1)-3x

\frac{1}{2} (\frac{3x+12x}{2} +1)-3x

\frac{1}{2} (\frac{15x}{2} +1)-3x

step-2: Distribute 1/2 inside

=\frac{1}{2} *\frac{15x}{2} +1*\frac{1}{2}-3x

=\frac{15x}{4} +\frac{1}{2} -3x

step-3: Combine like terms

=\frac{15x}{4}+3x +\frac{1}{2}

We can find common denominator

=\frac{15x}{4}-\frac{4*3x}{4*1} +\frac{1}{2}

=\frac{15x}{4}-\frac{12x}{4} +\frac{1}{2}

=\frac{15x-12x}{4} +\frac{1}{2}

=\frac{3x}{4} +\frac{1}{2}

we can also write it as in mixed form

=\frac{3}{4}x +\frac{1}{2}

so, we will get

\frac{1}{2} (\frac{3}{2} x+6x+1)-3x=\frac{3}{4}x +\frac{1}{2}

option-C.............Answer

5 0
4 years ago
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