All categories

4 years ago

What’s the inversion of g(x)=5x

Mathematics

1 answer:

shutvik [7]4 years ago

6 0

The inverse functions of g(x)=5x is x/5

You might be interested in

Evaluate 7 + (-3x^2) For x = 0 A. -2 B. 0 C. 4 D. 7

Goryan [66]

Answer: D. 7

Step-by-step explanation:

The problem tells you that x = 0 so replace everything that is x in the equation with 0 so the problem becomes

7 + (-3(0)^2)

Now we just solve the problem normally.

solve the problem in the parenthesis first, we must multiply -3 times 0^2 is 0

so now our problem is 7 + 0 which is 7

8 0

3 years ago

In ΔEFG, g = 4.3 cm, e = 9.1 cm and ∠F=116°. Find the length of f, to the nearest 10th of a centimeter.

8_murik_8 [283]

Answer:

11.6

Step-by-step explanation:

6 0

3 years ago

Is (-3,-9) a solution of the equation y = 3x ? O YES O NO O NOT A SOLUTION

melomori [17]

Answer:

Yes, (-3, -9) is a solution.

Step-by-step explanation:

y = 3x (-3,-9)

-9 = 3(-3)

-9 = -9

4 0

3 years ago

What’s the domain and range of: log(√(2x-1) + 3 ) Please explain how you got it too!!

Radda [10]

Two main facts are needed here:

1. The logarithm $\log x$ , regardless of the base of the logarithm, exists for $x>0$ .

2. The square root $\sqrt x$ exists for $x\ge0$ .

(in both cases we're assuming real-valued functions only)

By (2) we know that $\sqrt{2x-1}$ exists if $2x-1\ge0$ , or $x\ge\dfrac12$ .

By (1), we know that $\log(\sqrt{2x-1}+3)$ exists if $\sqrt{2x-1}+3>0$ , or $\sqrt{2x-1}>-3$ . But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require $x\ge\dfrac12$ , so the function has domain $\left[\dfrac12,\infty)$ .

To determine the range, we need to know that, in their respective domains, $\sqrt x$ and $\log x$ increase monotonically without bound. We also know that $x=\dfrac12$ at minimum, at which point the square root term vanishes, so the least value the function takes on is $\log3$ . Then its range would be $[\log3,\infty)$ .