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aleksklad [387]
4 years ago
14

What’s the inversion of g(x)=5x

Mathematics
1 answer:
shutvik [7]4 years ago
6 0
The inverse functions of g(x)=5x is x/5
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ANSWER ONLY IF U KNOW, OR THINK U KNOW.<br><br><br> (ILL MARK U BRAINLIEST)
alexandr1967 [171]

Answer:

I KNOW FOR SURE

Step-by-step explanation:

if that's all the question is then I definitely know the answer ;)

if you forgot to write the rest then hmu haha

4 0
3 years ago
Read 2 more answers
What is the first step to simplify the expression 64^42-[2(4-6)2]?
Marat540 [252]
Simplify what's in brackets first, then move to what's in the parenthesis
3 0
3 years ago
Help me please answer all because idk if I was correct scientific notation
valentina_108 [34]

Answer:

I think the first 4 are right

5-8

sorry I cant read it it it is too small so I will explain

5.1 x 10^-2 would be 0.051 just move the decimal left x spaces where x is the exponent

9

4.4 x 10^3

10

7.5 x 10^4

11

6.99 x 10^7

12

5.75 x 10^9

13

8.4 x 10^-2

14

9.9 x 10^-3

15

5.15 x 10^-7

16

3.07 x 10^-5

17

you got it right

18

you got it right

19

Singapore

Luxembourg

Australia

Egypt

Brazil

20

3,670,000,000

21

6.2 x 10^-6

22

125,000,000,000

1.25 x 10^11

Step-by-step explanation:

i hope I helped

3 0
3 years ago
If a circular property has a diameter of 50' and costs $120 per square foot, what is the cost of the property?
dusya [7]
Find area
area=pir^2
d/2=r=50/2=25

A=pi25^2
a=pi625
aprox pi=3.141592
a=1963.495
that is how many square feet
multiply that by 120
1963.495 times 120=$235,619.4
5 0
3 years ago
the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
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