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3 years ago

Suppose you deal three cards from a regular deck of 52 cards. What is the probability that they will all be jacks?

Mathematics

2 answers:

shusha [124]3 years ago

5 0

3 chances of jacks out of 52 cards

andrew-mc [135]3 years ago

4 0

<u>Answer:</u>

Probability of getting three jacks = $\frac { 3 } { 5 2 }$

<u>Step-by-step explanation:</u>

It is given that you deal three cards from a regular deck which contains 52 cards.

We are to find the probability of getting all three Jack cards.

We know that there are a total of 4 jacks in a regular deck of 52 cards.

Therefore, the probability of getting three jacks = $\frac { 3 } { 5 2 }$

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tankabanditka [31]

As, Opposite side of Special trapezoid is equal.So, it will be a Parallelogram.

ab=c d= 19 units

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3 years ago

Answer it pls option c

Troyanec [42]

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3 years ago

Drag values to complete each equation.

Alex777 [14]

Answer:

1. A. 1

2. D. $17^9$

Step-by-step explanation:

Properties used:

Power of a Power Property
Product Property
Quotient Property
Zero Exponent Property

1. First, let's deal with the numerator.

$(17^3)^6$ can be turned into $17^1^8$ by using the Power of a Power Property.

And then use the Product Property, $(17^1^8)(17^-^1^0) = 17^8$

So now, our fraction is this: $\frac{17^8}{17^8}$

All number over itself in a fraction is equal to 1. But you can also do this the mathmatic way using the Quotient Property: $\frac{a^m}{a^n} = a^m^-^n$ or $\frac{1}{a^(^n^-^m^)}$ . Which then you plug the numbers in: $\frac{17^8}{17^8} = 17^8^-^8 = 17^0$ . And since we know that in Zero Exponent Property: $a^0 = 1$ , we can see that $17^0 = 1$ . So either way, we get 1.