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Ivan
3 years ago
8

A car with an initial velocity of 16.0 meters per second east slows uniformly to 6.0 meters per second east in 4.0 seconds. What

is the acceleration of the car during this 4.0-second interval?
Physics
1 answer:
pychu [463]3 years ago
5 0
(6-16)/4.0=-2.5 m/s²
Acceleration of the car is -2.5 m/s²
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As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.33 m l
deff fn [24]

Answer: 62 μT

Explanation:

Given

Length of rod, l = 1.33 m

Velocity of rod, v = 3.19 m/s

Induced emf, e = 0.263*10^-3 V

Using Faraday's law, the induced emf of a rod can be gotten by the formula

e = blv where,

e = induced emf of the rod

b = magnetic field of the rod

l = length of the rod

v = velocity of the rod. On substituting, we have

0.263*10^-3 = b * 1.33 * 3.19

0.263*10^-3 = b * 4.2427

b = 0.263*10^-3 / 4.2427

b = 0.0000620 T

b = 62 μT

Thus, the strength of the magnetic field is 62 μT

8 0
3 years ago
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In order to be considered a semi-conductor the material must
wel
First one, for instance they become conductors or insulators depending on the temperature!
4 0
4 years ago
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4 of
Maksim231197 [3]

Answer:

all of the above????

Explanation:

my teacher told me.

8 0
3 years ago
Does anyone know how to do this question???<br><br> Force = 7kN <br> Pressure = 1mPa<br> Area = ?
Andreas93 [3]

Answer:

7000 m^2

Explanation:

Pressure=Force/Area

1=7000/Area

1(Area)=7000

Area=7000 m^2

5 0
3 years ago
Find the electron and hole concentrations and fermi level in silicon at 300 k for boron
gogolik [260]

To find the electron and hole concentrations and fermi levels in silicon at 300 k for boron, fermi level is 9.3 x 10^4 cm^-3.

<h3>Calculation and Explanation</h3>

Ionization energy for boron in Si, 0.045 eV

Fermi level in silicon,

300 K at 10^{15} cm^{-3} (Boron atoms)

All boron impurities are ionized, 300K

Electron, hole concentrations and Fermi levels is found out,

The value of Na = 10^{15} cm^{-3}

np = \frac{ni^2}{nA}

np = \frac{(9.65 x 10^9)^2}{10^15}

np= 9.3 x 10^4 cm^-3

Fermi level is calculated,

Ef - Ev = kT ln(NV/ND)

value of kT = 0.0259 eV (300° K)

So, substitution the values

Ef - Ev = kT ln(NV/ND)

Ef - Ev = 0.0259ln (2.66 x 10^{19} / 10^{15} )

Ef - Ev = 0.0259ln (26600)

Ef - Ev = 0.0259 x 10.18

Ef - Ev = 0.263 eV

What is ionization energy?

Ionization energy, also known as ionization energy (IE) or ionization energy (British English spelling), is the minimal amount of energy needed to free the most loosely bonded electron from an isolated gaseous atom, positive ion, or molecule in physics and chemistry.

To know more about ionization energy, visit:

brainly.com/question/16243729

#SPJ4

4 0
1 year ago
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