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Mama L [17]
3 years ago
10

Which of the following has zeros that are not significant?

Physics
1 answer:
guapka [62]3 years ago
4 0
10.0 J

if it was 10.01 it would be significant, but its 10.0 which makes it a whole number
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By what factor does the peak frequency change if the celsius temperature of an object is doubled from 20.0 ∘c to 40.0 ∘c?
mart [117]

Answer:

it increases by a factor 1.07

Explanation:

The peak wavelength of an object is given by Wien's displacement law:

\lambda=\frac{b}{T} (1)

where

b is the Wien's displacement constant

T is the temperature (in Kelvins) of the object

given the relationship between frequency and wavelength of an electromagnetic wave:

f=\frac{c}{\lambda}

where c is the speed of light, we can rewrite (1) as

\frac{c}{f}=\frac{b}{T}\\f=\frac{Tc}{b}

So the peak frequency is directly proportional to the temperature in Kelvin.

In this problem, the temperature of the object changes from

T_1 = 20.0^{\circ}+273=293 K

to

T_2 = 40.0^{\circ}+273 = 313 K

so the peak frequency changes by a factor

\frac{f_2}{f_1} \propto \frac{T_2}{T_1}=\frac{313 K}{293 K}=1.07

8 0
3 years ago
Which of the following is true about a planet orbiting a star in uniform circular motion? A. The direction of the velocity vecto
Luda [366]
<span>As it is uniform circular motion therefore speed is constant. Therefore we can rule out option B. Also in circular motion the direction of velocity vector changes therefore velocity can't be constant. Therefore option B is incorrect as well. Also centripetal acceleration is always towards the center so option D is wrong as well. That implies option A is correct.</span>
4 0
4 years ago
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How old was Antoine Lavoisier's wife when they married
Zepler [3.9K]

jsjshebsjsusunxndj 78

6 0
3 years ago
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. Orbit of a satellite It is advantageous to place communications satellites in a circular orbit so that their position is fixed
Alexxx [7]

Answer:

a) r = 4.22 10⁷ m, b)  v = 3.07 10³ m / s  and c)  a = 0.224 m / s²

Explanation:

a) For this exercise we will use Newton's second law where acceleration is centripetal and force is gravitational force

     F = m a

     a = v² / r

     F = G m M / r²

    G m M / r² = m v² / r

    G M / r = v²

The squared velocity is a scalar and this value is constant, so let's use the uniform motion relationships

     v = d / t

As the orbit is circular the distance is the length of the circle in 24 h time

     d = 2π r

     t = 24 h (3600 s / 1 h) = 86400 s

Let's replace

     G M / r = (2π r / t)²

     G M = 4 π² r³ / t²

     r = ∛(G M t² / (4π²)

     r = ∛( 6.67 10⁻¹¹ 5.98 10²⁴ 86400² / (4π²)) = ∛( 75.4 10²¹)

     r = 4.22 10⁷ m

b) the speed module is

    v = √G M / r

    v = √(6.67 10⁻¹¹ 5.98 10²⁴/ 4.22 10⁷

    v = 3.07 10³ m / s

c) the acceleration is

    a = G M / r²

    a = 6.67 10⁻¹¹ 5.98 10²⁴ / (4.22 10⁷)²

    a = 0.224 m / s²

5 0
3 years ago
In an exothermic reaction, the products have _____.
Sergio039 [100]

Answer: In an exothermic reaction, the products have  less energy than the reactants.

Explanation: There are two types of reactions:

1. Endothermic reactions: These are the reactions in which energy is required in the reaction. The energy of the products are more than the energy of the reactants.

2. Exothermic reactions: These are the reactions in which energy is released in the reaction. The energy of the products is less than the energy of the reactants.

Hence, in an exothermic reaction, the products have  less energy than the reactants.

8 0
4 years ago
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