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WITCHER [35]
2 years ago
11

using a lever to move a rock reduces the force a person must exert. what does it do to the work the person must do?

Physics
1 answer:
morpeh [17]2 years ago
3 0

Using a lever to move a rock reduces the force a person must exert . It also reduces the work (effort ) the person must do.

Using a lever decreases the input force required to lift up the load, for example if a force of 900N is required to lift the load without a lever . Using the lever the input force decreases to 500N and as we all know by the formulae of work done :

Work done ∝  force applied

By this equation we can conclude that if the force to be applied on the load reduces by the use of a lever therefore the work to be done on the load will also reduce .

You can get a additional information about the lever system below :

brainly.com/question/3522307

#SPJ4

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The energy required to start a reaction is called the activation energy. true false
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The energy required to start a reaction IS called the activation energy. TRUE

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3 years ago
Two objects are dropped from rest from the same height. Object A falls through a distance <img src="https://tex.z-dn.net/?f=d_A"
Alenkinab [10]

Answer:

The answer to your question is given below

Explanation:

Since both object A and B were dropped from the same height and the air resistance is negligible, both object A and B will get to the ground at the same time.

From the question, we were told that object A falls through a distance to dA at time t and object B falls through a distance of dB at time 2t.

Remember, both objects must get to the ground at the same time..!

Let the time taken for both objects to get to the ground be t.

Time A = Time B = t

But B falls through time 2t

Therefore,

Time A = Time B = 2t

Height = 1/2gt^2

For A:

Time = 2t

dA = 1/2 x g x (2t)^2

dA = 1/2g x 4t^2

For B

Time = t

dB = 1/2 x g x t^2

Equating dA and dB

dA = dB

1/2g x 4t^2 = 1/2 x g x t^2

Cancel out 1/2, g and t^2

4 = 1

4dA = dB

Divide both side by 4

dA = 1/4 dB

8 0
3 years ago
Consider the following statements. A. Heat flows from an object at higher temperature to an object at lower temperature; B. Heat
IgorC [24]

Only ' A ' is always true.<em> (choice-1)</em>

' B ' is not true when you drop a red hot spoon into cold soup.

' C ' is not true when you drop a red hot marble into a cool swimming pool.

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A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe
ikadub [295]

Answer:

f_{fr}=1590.85 N

Explanation:

Here the total force at the horizontal components will be equal to the centripetal force on the car. So we will have:

f_{fr}cos(25)+Nsin(25)=m\frac{v^{2}}{r} (1)

  • f(fr) is the friction force
  • N is the normal force

Now, the sum of forces at the vertical direction is equal to 0.

Ncos(25)-mg-f_{fr}sin(25)=0 (2)          

Let's combine (1) and (2) to find f(fr)

f_{fr}=\frac{(mv^{2}/r)-mgtan(25)}{cos(25)+tan(25)sin(25)}

f_{fr}=\frac{(600*30^{2}/120)-600*9.81*tan(25)}{cos(25)+tan(25)sin(25)}  

f_{fr}=1590.85 N

I hope it helps you!

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I need help algebra in physics
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Answer:

A: 0.26

Explanation:

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