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Radda [10]
3 years ago
11

Johnny walked to the other side of his building using the following steps: 10 meters North, 20 meters to the West, 40 meters Sou

th. What is Johnny's distance and displacement?
Physics
1 answer:
nataly862011 [7]3 years ago
6 0

<u>Answer: </u>

  Distance traveled = 70 meters

  Displacement = 36.06 meters

<u>Explanation: </u>

 Let north be positive Y and east be positive X

 10 meters north, displacement = 10 j meters

 20 meters west, displacement = -20 i meters

 40 meters south, displacement = -40 j meters

 Total displacement = (10 j - 20 i – 40 j) meters = (- 20 i - 30 j) meters

 Magnitude of displacement = \sqrt{20^2+30^2}=\sqrt{1300}= 36.06 meters

 Distance traveled = 10+20+40 = 70 meters

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Please help! the mass of an object is measured on a pan balance with a precision of 0.005 g and the recorded value of 128.01 g.
inysia [295]

Yes, these two objects have different masses.

<h3>How can we calculate that this statement is right ?</h3>

To calculate the precision of mass we are using the formula,

Precision(P) = \frac{m_1}{m_1+\triangle m}

Or,\trianglem=\frac{m_1}{P}-m₁

For the first case we are given,

m₁= The recorded value of mass

= 128.01 g

P= Precision of the mass

=0.005g

So, according to the formula, \trianglem will be,

\trianglem=  \frac{128.01}{0.005}-128.01

Or,\trianglem=25,473.99 g

Or,\trianglem=25.47 Kg

For the first case \trianglem is 25.47 Kg..

For the second case we are given,

m₁= The recorded value of mass

= 0.13 Kg

P= Precision of the mass

=0.005 Kg

So, according to the formula, \trianglem will be,

\trianglem= \frac{0.13}{0.005}-0.13

Or,\trianglem= 25.87 kg

For the second case \trianglem is 25.87 Kg.

For the two cases  \trianglem has different values, 25.47 Kg≠25.87 Kg.

Therefore we can conclude that, these two objects have different masses.

Learn more about Mass:

brainly.com/question/3187640

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7 0
1 year ago
The engineer of a passenger train traveling at 25.0m/s sights a freight train whose caboose is 200m ahead on the same track. The
Vika [28.1K]

Answer:

No, there won't be a collision.

Explanation:

We will use the constant acceleration formulas to calculate,

v = u + a*t

0 = 25 + (-0.1)*t

t = 250 seconds (the time taken for the passenger train to stop)

v^2 = u^2 + 2*a*s

0 = (25)^2  + 2*(-0.1)*s

s = 3125 m (distance traveled by passenger train to stop)

If the distance traveled by freight train in 250 seconds is less than (3125-200=2925 m) than the collision will occur

Speed*time = distance

Distance = (15)*(250)

Distance = 3750 m

As the distance is way more, there won’t be a collision

5 0
3 years ago
What must happen to an atom of magnesium in order to become a magnesium ion Mg+2?
igomit [66]

Answer:

Answer is: c. It must lose two electrons and become an ion.

Magnesium (Mg) is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons (two valence electrons).

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.

Explanation:

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leva [86]

Answer:

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