What are some of the similar features of position vs time and velocity vs time

<img src="https://tex.z-dn.net/?f=2.25%20%5Ctimes%2030" id="TexFormula1" title="2.25 \times 30" alt="2.25 \times 30" align="absm

Paraphin [41]

67.5 is the answer i believe!!

7 0

2 years ago

Read 2 more answers

Tarzan (75 kg) swings from 4 metres high on a vine down to ground level and catches Jane (50 kg). How fast are they moving after

Kruka [31]

Try this solution (if it is possible, check it in other sources):

1. for m_Tarzan=75kg., initial_height=4m., end_height=0 m. and g=10 N/kg. Energy is:

$E=m_{Tarzan}*(H_{initial}-H_{end})*g=75*4*10=3000(J).$

2. The same value of Energy is applied for m_Tarzan+Jane=75+50=125 kg.:

$E=\frac{m_{Tarzan+Jane}* Speed^2}{2}; \ => \ Speed=\sqrt{ \frac{2*E}{m_{Tarzan+Jane}}};$

3. According to the formula of the Speed:

Speed=sqrt(6000/125)=sqrt(48)=4sqrt(3)≈4*1.71=6.84 (m/s)

Answer: 6.84 (m. per sec.)

5 0

3 years ago

What type of weathering is best expressed in this weathered limestone?

DENIUS [597]

It seems that you have missed the necessary options for us to answer this question so I had to look for it. Anyway, here is the answer. The type of weathering that is best expressed in this weathered limestone is DISSOLUTION. Hope this answers your question. Have a great day!

6 0

3 years ago

Why is it a good idea to extend your bare hand forward when you are getting ready to catch a fast-moving baseball?

qaws [65]

Answer:d

Explanation:

It is good to extend your bare hand forward when you are getting ready to catch a fast-moving ball so you can pull your hand back, increasing the time to slow the ball thus decreasing the force.

While catching impulse is being transferred to hands imparting great force, lowering hand would increase the time so that average force decreases and chances to drop the ball also decreases.

4 0

3 years ago

A piece of aluminum (bulk modulus 7.1 x 1010 N/m2) is placed in a vacuum chamber where the air pressure is 0.781 x 105 Pa. The v

Jet001 [13]

Answer:

${\dfrac{\Delta V}{V}}=11\times 10^{-7}$