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wolverine [178]
3 years ago
11

Select the correct answer. Using the right hand rule, what do the three numbered vectors represent in the diagram below? A. 1) f

orce; 2) electric current; 3) magnetic field B. 1) electric current; 2) magnetic field; 3) force C. 1) magnetic field; 2) force; 3) electric current D. 1) electric current 2) force; 3) magnetic field E. 1) magnetic field; 2) electric current; 3) force
Physics
2 answers:
beks73 [17]3 years ago
4 0

Answer:

E. 1) magnetic field 2) electric current 3) force

Explanation:

plato

kirill [66]3 years ago
3 0

Answer:

Explanation:

Using the right-hand rule, the correct answer is:

A) Magnetic field

B) Electric current

C) Force

The equation corresponding to this graphical representation is

F = IBL

where I is the current, B the magnetic field, L the length of the wire and F the magnetic force.

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A 4-kg hammer is lifted to a height of 10 m and dropped from rest. What was the velocity (in m/s) of the hammer when it was at a
ipn [44]

Answer:

v = 10.84 m/s

Explanation:

using the equation of motion:

v^2 = (v0)^2 + 2×a(r - r0)

<em>due to the hammer starting from rest, vo = 0 m/s and a = g , g is the gravitational acceleration.</em>

v^2 = 2×g(r - r0)

v = \sqrt{2×(-9.8)×(4 - 10)}

  = 10.84 m/s

therefore, the velocity at r = 4 meters is 10.84 m/s

4 0
3 years ago
Samples of different materials, A and B, have the same mass, but the sample
Effectus [21]

Answer:

B. The particles that make up material B have more mass than the

particles that make up material A.

Explanation:

3 0
3 years ago
Glycerin is poured into an open U-shaped tube until the height in both sides is 20cm. Ethyl alcohol is then poured into one arm
Liula [17]

Answer:

7.5 cm

Explanation:

In the figure we can see a sketch of the problem. We know that at the bottom of the U-shaped tube the pressure is equal in both branches. Defining \rho_A: Ethyl alcohol density and \rho_G: Glycerin density , we can write:

\rho_A\times g \times h_1 + \rho_G \times g \times h_2 = \rho_G \times g \times h_3

Simplifying:

\rho_A\times h_1 = \rho_G \times (h_3 - h_2) (1)

On the other hand:

h_1 + h_2 = \Delta h + h_3

Rearranging:

h_1 - \Delta h = h_3 - h_2 (2)

Replacing  (2) in (1):

\rho_A\times h_1 = \rho_G \times (h_1 - \Delta h)

Rearranging:

\frac{h_1 \times (\rho_A - \rho_G)}{- \rho_G} = \Delta h

Data:

h_1 = 20 cm; \rho_A = 0.789 \frac{g}{cm^3}; \rho_G = 1.26 \frac{g}{cm^3}

\frac{20 cm \times (0.789 - 1.26) \frac{g}{cm^3}}{- 1.26\frac{g}{cm^3}}  = \Delta h

7.5 cm =  \Delta h

7 0
3 years ago
Easy physics question help.!!!
stellarik [79]

Answer: This is not easy lol

Explanation:

3 0
3 years ago
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