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Anarel [89]
3 years ago
6

An object accelerates in a direction that is always perpendicular to its motion.what is the effect if any of the acceleration on

the objects speed and direction
Physics
1 answer:
mars1129 [50]3 years ago
3 0
If its accelerating it will increase velocity in the direction of the acceleration which is perpendicular to the velocity.
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The question is on the picture
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<em> think 2 also if not im so sorry  but i think it is :)</em>

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Diffrence between vector and scalar
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Vector has a direction and a magnitude, scalar only has a magnitude

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A proton and an electron are moving in the +x direction in a magnetic field in the +z
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Answer:

Explanation:

A proton and electron are moving in the positive x direction, this shows that their velocity will be in the positive x direction

V = v•i

Magnetic field Is the positive z direction

B = B•k

A. For proton.

Proton has a positive charge of q

Direction of force on proton

Force is given as

F = q(v×B)

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F = qvB (i×k)

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F = -qvB •j

Then, for the positive charge, the force will act in the negative direction of the y-axis

B. For electron

Electron has a negative of -q

Direction of force on proton

Force is given as

F = q(v×B)

F = -q( v•i × B•k)

F = -qvB (i×k)

From vectors i×k = -j

F = --qvB •j

F = qvB •j

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3 years ago
What are some of the physical benefits to be derived from aerobic
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Some of the benefits are increased heart muscles, increase in blood flow, and reduced body fat
6 0
4 years ago
Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 320 N/C. (a) What is the ma
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(a) The magnitude of the acceleration of the electron is 5.62 x 10¹³ m/s².

(b) The speed of the electron after the given time is  4.78 x 10⁵ m/s.

<h3>Acceleration of the electron</h3>

The acceleration of the electron is calculated as follows;

F = qE

ma = qE

a = qE/m

a = (1.6 x 10⁻¹⁹ x 320)/(9.11 x 10⁻³¹)

a = 5.62 x 10¹³ m/s²

<h3>Speed of the electron</h3>

v = at

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v = 4.78 x 10⁵ m/s

Learn more about speed here: brainly.com/question/4931057

#SPJ1

7 0
2 years ago
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