<h2>
Answer: 1000 J</h2>
The Work 
done by a Force 
refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.
It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:
Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:
(1)
When they are not parallel, both directions form an angle, let's call it 
. In that case the expression to calculate the Work is:
(2)
For example, in order to push the 200 N box across the floor, you have to apply a force along the distance 
to overcome the resistance of the weight of the box (its 200 N).
In this case both <u>(the force and the distance in the path) are parallel</u>, so the work performed is the product of the force exerted to push the box 
by the distance traveled . as shown in equation (1).
Hence:
>>>>This is the work
Answer:
Q = 590,940 J
Explanation:
Given:
Specific heat (c) = 1.75 J/(g⋅°C)
Mass(m) = 2.01 kg = 2,010
Change in temperature (ΔT) = 191 - 23 = 168°C
Find:
Heat required (Q)
Computation:
Q = mcΔT
Q = (2,010)(1.75)(168)
Q = 590,940 J
Q = 590.94 kJ
Answer:
Explanation:
The dimensions 
have the highest cross-sectional area combination of 
.
-Resistance reduces with an increase in cross sectional area.
-
Electrons have alarger area to flow through.
Answer:
the time it will take the element to decay to 1.9 g is 34.8 mins.
Explanation:
Given;
half life of Nitrogen, t = 10 min
initial mass of the element, N₀ = 20 g
final mass of the element, N = 1.9 g
The time taken for the element to decay to final mass is calculated as follows;
time (min) mass remaining
0 ----------------------------------20 g
10 mins ------------------------- 10 g
20 mins ------------------------- 5 g
30 mins -------------------------- 2.5 g
40 mins --------------------------- 1.25 g
Interpolate between 2.5 g and 1.25 to obtain the time for 1.9 g
30 min ------------------------- 2.5 g
x ----------------------------------- 1.9 g
40 min -------------------------- 1.25 g
Therefore, the time it will take the element to decay to 1.9 g is 34.8 mins.
