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Helga [31]
2 years ago
14

What happens when charged object is brought near uncharged object? Attract or Repel ?

Physics
2 answers:
Pie2 years ago
6 0
<span>when a charged object is brought near uncharged object it will attract towards charge object
</span>its charges rearrange themselves. in such a way that Those which are  attracted to the charged object move towards the charged object and those that are charges move away. an this phenomena is called as polarization.<span> 
</span>hope it helps
Makovka662 [10]2 years ago
5 0
When a charged object is brought near to but does not touch a neutral object, it causes the side of the neutral object that the charged object is near to become the other charge. It causes charge migration within the neutral object so the two charges (positive and negative) move to opposite sides of the object. Because the two objects do not touch, they do not repel each other, but rather have a slight attraction because of charge migration. If the two object were to touch then they would repel.
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What is the formula for conservation of momentum
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Answer:

The general equation for conservation of momentum during a collision between n number of objects is given as: [m i ×v i a ] = [m i ×v i b ] Where m i is the mass of object i , v i a is the velocity of object i before the collision, and v i b is the velocity of object i after the collision.

Explanation:

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2 years ago
A car changes velocity at a constant acceleration of 2.5m/s to reach 43.7m/s in 2.7 s how fast was the car moving when it began
Montano1993 [528]

The formula we can use in this case is:

v = v0 + a t

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So finding for v0:

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3 years ago
On a playground slide, a child has potential energy that decreases by 1000 J while her kinetic energy increases by 900 J. what o
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1 year ago
The two-second rule applies to any speed __________ A. in all weather conditions. B. in ideal weather and road conditions. C. in
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Answer:

The answer is A

Explanation:

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Read 2 more answers
A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When re
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Answer:

(1) V = 0.2 J (2) 0.05J

Explanation:

Solution

Given that:

K = 160 N/m

x = 0.05 m

Now,

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Thus,

V = 1/2 kx² = 0.5 * 160 * (0.05)²

Therefore V = 0.2 J

(2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.

By using the energy conversion, we have the following

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The internal energy = 0.2 -0.15

=0.05J

8 0
3 years ago
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