The delta G for the dissociation is 87,865 joule/kg.
The process is non-spontaneous because the value of Gibbs free energy is positive.
<h3>What is dissociation?</h3>
The breaking up of a compound into a simpler form that can be recombined under other conditions.
Given,
H = 145 kJ
Delta S = 195 J/k
Determining the G using the following process:
G = H -TS
G = 87,865 Joules/K
Thus, the value of Delta G is 87,865 and the process is non-spontaneous.
Learn more about dissociation here:
brainly.com/question/4431132
Answer:
The final concentration is 0.288 M (approximately)
Explanation:
Using dilution formula:
C1V1 = C2V2
Where C1 is the initial concentration
C2 is the final concentration
V1 is the initial volume
V2 is the final volume
In the first dilution, C1 = 1.8M,
V1 =71mL, V2 = 218mL from the formula C2 = 1.8 ×71/281
=0.5862M
In the second dilution,
C1 = 0.5862M, V1 = 109mL, V2 = 222 mL (109+113)
C2 = 0.5862 × 109 ÷ 222
= 0.288 M (approximately) assuming volume is additive.
6 grams of Carbon is it’s mass
<u>Explanation:</u>
First we have to divide the given number of atoms by the Avogadro's number , so that we will get the number of moles as 1/2.
Then the 1/2 moles of carbon is multiplied by the molar mass of Carbon which is 12 g/mol, we will get the mass of carbon as 6 grams.
So the mass of the carbon obtained is 6 grams.
First question. Applying ideal gas equation PV=nRT, P= 101.3 x 10³Pa = 1atm. therefore, 1 x 260 x 10^-3 = n x 0.082 x 294.( Temperature in kelvin=273+21). n = 0.01 moles. Volume of gas at STP= n x 22.4 = 0.01x22.4 = 0.224L. Hope this helps