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Sergeeva-Olga [200]
3 years ago
5

Acts as the digestive system inside a cell. It helps to break down old or unneeded parts of the cell, and substances that have b

een brought into the cell from the outside. WHO I AM?

Chemistry
1 answer:
DIA [1.3K]3 years ago
5 0

Answer:

I think it is enzymes

Explanation:

You might be interested in
Some SbCl5 is allowed to dissociate into SbCl3 and Cl2 at 521 K. At equilibrium, [SbCl5] = 0.195 M, and [SbCl3] = [Cl2] = 6.98×1
Brilliant_brown [7]

Answer:

a) The equilibrium will shift in the right direction.

b) The new equilibrium concentrations after reestablishment of the equilibrium :

[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M

[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

Explanation:

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increase in amount of reactant

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of SbCl_5 is  increasing .So, the equilibrium will shift in the right direction.

b)

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

Concentration of SbCl_5  = 0.195 M

Concentration of SbCl_3  = 6.98\times 10^{-2} M

Concentration of Cl_2  = 6.98\times 10^{-2} M

On adding more [SbCl_5 to 0.370 M at equilibrium :

SbCl_5(g)\rightleftharpoons SbCl_3(g) + Cl_2(g)

Initially

0.370 M         6.98\times 10^{-2}M    

At equilibrium:

(0.370-x)M   (6.98\times 10^{-2}+x)M  

The equilibrium constant of the reaction  = K_c

K_c=2.50\times 10^{-2}

The equilibrium expression is given as:

K_c=\frac{[SbCl_3][Cl_2]}{[SbCl_5]}

2.50\times 10^{-2}=\frac{(6.98\times 10^{-2}+x)M\times (6.98\times 10^{-2}+x)M}{(0.370-x) M}

On solving for x:

x = 0.0233 M

The new equilibrium concentrations after reestablishment of the equilibrium :

[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M

[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M

3 0
3 years ago
Methyl violet is an indicator that changes color over a range from pH=0.0 to pH=1.6. What is Ka of methyl violet?
Tju [1.3M]

it's basic in nature

7 0
3 years ago
A: IF TWO ANGLES ARE SUPPLEMENTARY, THEN ONE ANGLE IS ACUTE AND ONE IS OBTUSE.
nydimaria [60]

Answer:

True or False?

Explanation:

A. False and or sometimes.

B. False and or sometimes.

What is our main objective here??????????????????

3 0
2 years ago
Which of these structures is least in danger of chemical weathering?
xxMikexx [17]

Answer: a bench made of composite plastic

Explanation:

The chemical weathering can be defined as the process in which a chemical causes the degradation and decomposition of the rocks into small particles. The iron rods, feldspar, and marble will weather considerably with a greater danger as the have a strong solid body. But plastic when exposed to a chemical agent usually melts and thus there is least or no danger of chemical weathering of plastic.

4 0
3 years ago
Give one example each for a binary compound and a ternary compound. (A ternary compound is one that contains three different ele
Sedbober [7]

Answer and Explanation:

BINARY COMPOUND: A binary compound is that compound which is made up of exactly two elements there are a lot binary compound present for example :H_2O, NaCl,NH_3,H_2S etc

TERNARY COMPOUND : A ternary compound is that compound which is made up of exactly three elements there are a lot binary compound present for example : Na_2SO_4,H_2SO_4,CH_3C00H  etc

7 0
3 years ago
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