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kotegsom [21]
3 years ago
9

How do I solve this problem?

Chemistry
1 answer:
JulijaS [17]3 years ago
5 0
First question. Applying ideal gas equation PV=nRT, P= 101.3 x 10³Pa = 1atm. therefore, 1 x 260 x 10^-3 = n x 0.082 x 294.( Temperature in kelvin=273+21). n = 0.01 moles. Volume of gas at STP= n x 22.4 = 0.01x22.4 = 0.224L. Hope this helps
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LiRa [457]
Data:
Q (Amount of heat) = 832 J
m (mass) = ?
c (Specific heat) = <span>0.90 J/(g × ° C)
T (final) = 97 ºC
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</span>ΔT = T - To → ΔT = 97 - 20 → ΔT = 77 ºC

Formula:
Q = m*c*ΔT

Solving:
Q = m*c*ΔT
832 = m*0.90*77
832 = 69.3m
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m =  \frac{832}{69.3}
\boxed{\boxed{m \approx 12.00\:g}}\end{array}}\qquad\quad\checkmark
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Hello! Greetings from Turkey! :)

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