Ask question

Ask question

All categories

3 years ago

14

An aqueous solution containing 35.5 g of an unknown molecular (non-electrolyte) compound in 151.0 g of water was found to have a

freezing point of -1.3 ?C

1 answer:

Tasya [4]3 years ago

8 0

ccccccccccccccccccccccccccccccccccc

You might be interested in

(1) Complete the word equation for the complete combustion of methane in

Deffense [45]

Cooled in ice to help the water vapour condense. Tube 2 – contains lime water, goes cloudy to show the presence of carbon dioxide. Word equation: (hydrocarbon + oxygen → carbon dioxide + water) Methane + oxygen → carbon dioxide + water.

6 0

2 years ago

What is the main reason that attitudes are more often revealed in spoken rather than written language?

musickatia [10]

I believe the answer is D.

6 0

3 years ago

What is transportation?

Mandarinka [93]

Movement from place to palce

3 0

3 years ago

Read 2 more answers

A compound that yields hydrogen ions when dissolved in a solution

Mumz [18]

A compound that yields hydrogen ions when dissolved in a solution is an acid.

An example is an <em>aqueous solution of HCl.</em>

7 0

3 years ago

A solution is prepared at that is initially in benzoic acid , a weak acid with , and in sodium benzoate . Calculate the pH of th

Kisachek [45]

Answer:

$pH=4.1$

Explanation:

Hello,

In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:

$pH=pKa+log(\frac{[base]}{[acid]} )$

Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:

$pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1$

Regards.

3 0

3 years ago