Answer:
Explanation:
Molar mass:
Molar mass of substance is sum of atomic weight of all the atoms of elements present in it.
HCl
Atomic weight of hydrogen = 1.008 amu
Atomic weight of chlorine = 35.5 amu
Atomic weight of HCl = 1.008+ 35.5 = 36.508 g/mol
K₂CO₃:
Atomic weight of potassium = 39.0893 × 2 = 78.1786 amu
Atomic weight of carbon = 12 amu
Atomic weight of oxygen = 16×3 = 48 amu
Atomic weight of K₂CO₃ = 48+12+ 78.1786 = 138.178 g/mol
Ca(OH)₂:
Atomic weight of calcium = 40 amu
Atomic weight of oxygen = 16× 2 amu = 32 amu
Atomic weight of hydrogen = 1.008× 2 = 2.016 amu
Atomic weight of Ca(OH)₂ = 74.016 g/mol
Na₃PO₄:
Atomic weight of sodium = 23×3= 69 amu
Atomic weight of phosphorus = 31 amu
Atomic weight of oxygen = 16 × 4 = 64 amu
Atomic weight of Na₃PO₄= 69+31+64 = 164 g/mol
Explanation:
The electronic configuration of the element given is:
[Ne] 3s 3p
The family is the group the compound belongs on the periodic table. It is given by the number of valence electrons it contains.
The period is given by the principal quantum number. The principal quantum number is 3
The Orbital block is in the p-block
The question is incomplete, here is the complete question:
A chemist makes 600. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a stock solution of 0.00154 mol/L magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.
<u>Answer:</u> The concentration of chemist's working solution is
<u>Explanation:</u>
To calculate the molarity of the diluted solution (chemist's working solution), we use the equation:
where,
are the molarity and volume of the stock magnesium fluoride solution
are the molarity and volume of chemist's magnesium fluoride solution
We are given:
Putting values in above equation, we get:
Hence, the concentration of chemist's working solution is
Each chemical reaction, you may say that there are many possible balanced reactions since the coefficients of the reactants and of the products can be another set of numbers as long as the ratios of the compounds would be the same. The most preferred balanced reaction would be the reaction which have the lowest value of coefficients. Example would be the reaction of HCl and NaOH.
HCl + NaOH = NaCl + H2O (This would be the most preferred one since the coefficients are in the lowest value)
Other equivalents would be:
2HCl + 2NaOH = 2NaCl + 2H2O
3HCl + 3NaOH = 3NaCl + 3H2O
4HCl + 4NaOH = 4NaCl + 4H2O