Answer:
0.054 mol O
Explanation:
<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of carbon in a sample of acetic acid. How many moles of oxygen are in the sample?</em>
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Step 1: Given data
- Chemical formula of acetic acid: CH₃CO₂H
- Moles of carbon in the sample: 0.054 moles
Step 2: Establish the appropriate molar ratio
According to the chemical formula, the molar ratio of C to O is 2:2.
Step 3: Calculate the moles of oxygen in the sample
We will use the molar ratio to determine the moles of oxygen accompanying 0.054 moles of carbon.
0.054 mol C × (2 mol O/2 mol C) = 0.054 mol O
Answer:
Explanation: E. 12 because it has the highest acidity rate.
Answer:
The molarity of this solution is 0.156 M
Explanation:
Step 1: Data given
Mass of Ba(OH)2 = 1.90 grams
Molar mass Ba(OH)2 = 171.34 g/mol
Volume of the solution = 71.1 mL = 0.0711 L
Step 2: Calculate moles Ba(OH)2
Moles Ba(OH)2 = mass Ba(OH)2 / molar mass Ba(OH)2
Moles Ba(OH)2 = 1.90 grams / 171.34 g/mol
Moles Ba(OH)2 = 0.0111 moles
Step 3: Calculate molarity
Molarity solutin = moles Ba(OH)2 / volume solution
Molarity solution = 0.0111 moles / 0.0711 L
Molarity solution = 0.156 M
The molarity of this solution is 0.156 M