The third option, 2,2,1,2
Answer:
4KO₂ + 2CO₂ -> 2K₂CO₃ + 3O₂
<u> Step 1: Find the moles of O₂.</u>
n(O₂) = mass/ Mr.
n(O₂) = 100 / 32 = 3.125 mol
<u>Step 2: Find the ratio between KO₂ and O₂.</u>
<u>KO₂ </u> : <u> O₂</u>
4 : 3
4/3 : 1
(4*3125)/3 : 3.125
=4.167 mol of KO₂
Thus now we know, to produce 100 g of O₂, we need 4.167mol of KO₂
<u>Step 3: Find the mass of KO₂:</u>
<u />
mass = mol * Mr. (KO₂)
Mass = 4.167* 71.1
Mass = 296.25 g
32.) 55.6 mL HCl
33.) 0. 128 M
Answer: 50 grams
Explanation: The water is still only going to be 50 grams. Although it’s in a different state, it didn’t gain or lose any water while being frozen.
The cell notation is
║
and the cell potential is 0.464
The reaction occurred while losing of hydron is known as oxidation reaction
We can also tell that the reaction occurred while gaining of oxygen atom is known as oxidation reaction.
The reaction occurred while gaining of hydrogen is known as reduction reaction or we can say that the reaction occurred while losing oxygen atom is known as reduction reaction
An electrochemical cell's cell potential is defined as the difference in potential between two half cells. The electrons' capacity to go from one half cell to the other is what causes the potential difference. As a result of the chemical reaction being a redox reaction, electrons can travel across electrodes.
Calculating the Cell potential
E°cell = E°(reduction) - E°(oxidation)
= 0.34 - (-0.0124)
= 0.464
Hence the cell potential is 0.464
Learn more about Cell potential here
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