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maxonik [38]
2 years ago
9

hi:) evaporation is the process by which liquids changes to gas at temperatures lower than boiling point. But why can’t liquids

evaporate at their boiling point? Is that because liquids will boil instead of evaporate? Anyone able to help I’m rlly confused.
Chemistry
2 answers:
Sindrei [870]2 years ago
6 0

Answer:

evaporation is the process by which liquids changes to gas at temperatures lower than boiling point. But why can’t liquids evaporate at their boiling point? Is that because liquids will boil instead of evaporate?

Evaporation only take place at a certain temperature or it is high at a particular temperature which makes it to be rapid then, when liquid is heated, at a temperature the vapor leaves and evaporates in gaseous form known as vapor to the atmosphere. Evaporation takes place below the temperature of boiling point and above it but the rapidity depends on the temperature, the higher the temperature the rapid the evaporation takes place

Explanation:

fiasKO [112]2 years ago
5 0

Answer: I’m not sure if this will help, but once it reaches its boiling point and actually makes the state of matter change from a liquid to gas, that is referred to as vaporization. Evaporation occurs below the boiling point and vaporization occurs at or above it.

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A student was titrating the calcium and water solution and notice the formation of bubbles in the flask. which description would
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A chemist titrates of a hypochlorous acid solution with solution at . Calculate the pH at equivalence. The of hypochlorous acid
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The question is incomplete, here is the complete question:

A chemist titrates 110.0 mL of a 0.2412 M hypochlorous acid (HCIO) solution with 0.0613 M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of hypochlorous acid is 7.50. Round your answer to 2 decimal places

<u>Answer:</u> The pH of the solution is 10.09

<u>Explanation:</u>

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=0.2412M\\V_1=110.0mL\\n_2=1\\M_2=0.0613M\\V_2=?mL

Putting values in above equation, we get:

1\times 0.2412\times 110.0=1\times 0.0613\times V_2\\\\V_2=\frac{1\times 0.2412\times 110.0}{1\times 0.0613}=432.8mL

At equivalence, the number of moles of acid is equal to the number of moles of base. Also, the moles of salt which is NaClO will also be the same.

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

  • <u>For HClO:</u>

Molarity of HClO solution = 0.2412 M

Volume of solution = 110.0 mL

Putting values in equation 1, we get:

0.2412M=\frac{\text{Moles of HClO}\times 1000}{110}\\\\\text{Moles of HClO}=\frac{(0.2412\times 110)}{1000}=0.026532mol

  • <u>For NaClO:</u>

Moles of NaClO = 0.026532 moles

Volume of solution = [432.8 + 110] mL = 542.8 mL

Putting values in above equation, we get:

\text{Molarity of NaClO}=\frac{0.026532\times 1000}{542.8}=0.0489M

To calculate the pH of the solution, we use the equation:

pH=7+\frac{1}{2}[pK_a+\log C]

where,

pK_a = negative logarithm of weak acid which is hypochlorous acid = 7.50

C = concentration of the salt = 0.0489 M

Putting values in above equation, we get:

pH=7+\frac{1}{2}[7.50+\log (0.0489)]\\\\pH=7+3.09=10.09

Hence, the pH of the solution is 10.09

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