When Ka =1.37 x 10^-4
∴Pka = - ㏒Ka
= -㏒ 1.37 x 10^-4
= 3.86
According to H- H equation:
when PH = PKA + ㏒[conjugate base / weak acid]
when the lactate is the conjugate base and lactic acid is the weak acid
∴ PH = Pka +㏒[lactate] / [lactic acid]
so, by substitution:
4.49 = 3.86 + ㏒[lactate]/[lactic acid]
∴[lactate]/[lactic acid] = 4.3
∴ [lactic acid] / [lactate] = 1/4.3
= 0.23
Cylinder A - Adding 25 grams raised the water level by roughly 3.2 mL
Cylinder B - Adding 25 grams raised the water level by roughly 2.8 mL
Cylinder C - Adding 25 grams raised the water level by roughly 3.5 mL
Calculate grams/mL (density)
A. 25 g/3.2 mL = 7.8125 g/mL = Iron
B. 25 g/2.8 mL = 8.9286 g/mL = Nickel
C. 25 g/3.5 mL = 7.1429 g/mL = Zinc
Hope I helped!
Answer:
ECUACIÓN:HClO 2 + H 2O → ClO− 2 + H 3O
ACIDO: HClO2
BASECONJUGADA:ClO-2
Explanation:
Answer:
RNA molecules
Explanation:
RNA molecules carry the instructions that are necessary to create proteins