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2 years ago

What are your main fears about this class (if any)?

Chemistry

2 answers:

netineya [11]2 years ago

8 0

This is based on your personal opinion lol but ig you can say public speaking

love history [14]2 years ago

5 0

Answer:

sitting n front of class

reading out loud

and being stressed

and being bullied

Explanation:

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Picture below<br><br> need done by 2:30<br><br><br><br> thanks, God bless your week

Leviafan [203]

1. $\sf \bf {\boxed {\mathbb {Evaporation}}}$ - The changing of liquid to a gas.

2. $\sf \bf {\boxed {\mathbb {Automobile}}}$ - The major source of pollution.

3. $\sf \bf {\boxed {\mathbb {Greenhouse \:effect}}}$ - Carbon dioxide and water vapor trapping heat given off by Earth.

4. $\sf \bf {\boxed {\mathbb {Ozonosphere}}}$ - Layer absorbing ultraviolet rays.

5. $\sf \bf {\boxed {\mathbb {Condensation}}}$ - The changing of a gas to a liquid.

6. $\sf \bf {\boxed {\mathbb {Ionosphere}}}$ - Layer responsible for reflecting radio waves.

7. $\sf \bf {\boxed {\mathbb {Troposphere}}}$ - The layer in which weather changes.

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

5 0

2 years ago

Read 2 more answers

What is the % Yield if 3.8 g of Cu was produced?

seraphim [82]

83.9 is the answer i’m pretty sure

3 0

2 years ago

Charles’ Law can be expressed mathematically as V=kT. If the constant k for 6.0 L of gas is 0.020 L/K (liters per kelvin), what

kozerog [31]

Answer: 300 K

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$ (At constant pressure and number of moles)

$V=kT$

Given : V= 6.0 L

k= 0.020 L/K

T=?

$6.0=0.020LK^{-1}\times T$

$T=300 K$

Thus temperature of the gas is 300 K.

3 0

2 years ago

If a mass of a cube were 48.0g and its volume 24.0 cm3 what would its density be

EastWind [94]

Answer:

<h3>The answer is 2 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 48 g

volume = 24 cm³

We have

$density = \frac{48}{24} \\$

We have the final answer as

Hope this helps you

5 0

2 years ago

The decomposition of acetaldehyde is a second order reaction with a rate constant of 4.71 10−8 L/mol/s. What is the instantaneou

pochemuha

Answer: Rate of decomposition of acetaldehyde in a solution is $1.45\times 10^{-14}mol/Ls$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For a reaction : $A\rightarrow products$

$Rate=k[A]^x$

k= rate constant

x = order of the reaction = 2

$Rate=4.71\times 10^{-8}L/mol/s\times {5.55\times 10^{-4}M}^2$

$Rate=1.45\times 10^{-14}$

Thus rate of decomposition of acetaldehyde in a solution is $1.45\times 10^{-14}mol/Ls$

6 0

2 years ago

What are your main fears about this class (if any)?​

What are your main fears about this class (if any)?