Given the position function <em>s(t)</em>, you can get the acceleration function by differentiating <em>s</em> twice:
velocity = <em>s'(t)</em> = -5 sin(<em>t </em>) + 3 cos(3<em>t</em> )
acceleration = <em>s''(t)</em> = -5 cos(<em>t</em> ) - 9 sin(3<em>t</em> )
Then when <em>t</em> = <em>π</em>, the particle's acceleration is
<em>s''(π)</em> = -5 cos(<em>π</em>) - 9 sin(3<em>π</em>)
… = -5 • (-1) - 9 • 0 = 5
Answer:
9
Step-by-step explanation:
Answer:
plane HNA, HMB, ANG ...
Step-by-step explanation:
Any combination of three points on plane K will work unless all three are on the same line.
Answer:
= 3 (3x + 5y)
Step-by-step explanation:
First find the GCF of 9 and 15 which would be 3. Then the GCF which is 3 is placed on the left of the parentheses. then you plug in the numbers. So 9x divided by 3 is 3x, and 15y divided by 3 is 5y.
It will take 12 people to finish the turkey
