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asambeis [7]
3 years ago
8

Calculate the number of moles in the 2.00-L volume of air in the lungs of the average person. Note that the air is at 37.0°C (bo

dy temperature) and that the total volume in the lungs is several times the amount inhaled in a typical breath as given in
Chemistry
1 answer:
7nadin3 [17]3 years ago
7 0

Answer:

The number of mole = 0.079 mole.

Explanation:

According to ideal gas equation,

PV = nRT.................... equation 1

Where P = pressure of the air, V = volume of the air, n = number of moles, R = molar gas constant, T = Temperature in (Kelvin), R = molar gas constant

Making n the subject of equation 1

n = PV/RT................... equation 2.

Where P = 101325 pa = 1 atm

V = 2.00 L = 2.00 dm³

T = 37 = 37 + 273 = 310 K, R= 0.082 atm/(dm³Kmol)

Applying these values in equation 1,

n = (2×1)/(310×0.082)

n = 2/25.42

n = 0.079 mole

Therefore the number of mole = 0.079 mole.

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2 years ago
15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl
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Answer:

The answer to your question is 41.6 g of AgCl

Explanation:

Data

mass of NH₄Cl = 15.5 g

mass of AgNO₃ = excess

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Process

1.- Write the balanced chemical reaction.

              NH₄Cl  +  AgNO₃   ⇒   AgCl  +  NH₄NO₃

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3.- Calculate the theoretical yield

                 53.5 g of NH₄Cl -------------------- 143.5 g of AgCl

                  15.5 g of NH₄Cl  -------------------    x

                         x = (15.5 x 143.5) / 53.5

                         x = 2224.25 / 53.5

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75.8 g H₂O × (572 kJ/36.03 g H₂O) = 1.20 × 10³ kJ

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