Question

Calculate the number of moles in the 2.00-L volume of air in the lungs of the average person. Note that the air is at 37.0°C (body temperature) and that the total volume in the lungs is several times the amount inhaled in a typical breath as given in

Answer 1

Answer:

The number of mole = 0.079 mole.

Explanation:

According to ideal gas equation,

PV = nRT.................... equation 1

Where P = pressure of the air, V = volume of the air, n = number of moles, R = molar gas constant, T = Temperature in (Kelvin), R = molar gas constant

Making n the subject of equation 1

n = PV/RT................... equation 2.

Where P = 101325 pa = 1 atm

V = 2.00 L = 2.00 dm³

T = 37 = 37 + 273 = 310 K, R= 0.082 atm/(dm³Kmol)

Applying these values in equation 1,

n = (2×1)/(310×0.082)

n = 2/25.42

n = 0.079 mole

Therefore the number of mole = 0.079 mole.