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3 years ago

Fungi exist primarily in the form of long filaments called _____.

Chemistry

2 answers:

Andru [333]3 years ago

7 0

Answer:

fungi exist primarily in the form of long, tubular-like filaments called hyphae. a large amount of these hyphae all branched together make up a mycelia, or plurally mycelium.

lisabon 2012 [21]3 years ago

3 0

The filaments are called Hyphae.

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In the sodium-potassium pump, sodium ion release causes two K ions to be released into the cell. __________________ True False

Solnce55 [7]

Answer:

false

Explanation:

As we know that in sodium-potassium pump .

sodium potassium move 3Na+ outside the cells

and moving 2k+ inside the cells

so that we can say that given statement is false

Answer FALSE

6 0

3 years ago

Calculate the mass in grams of each sample. 4.88x10^20 H2O2 molecules

AleksAgata [21]

4.88x10^20 H2O2 molecules

5 0

3 years ago

Which of these statements is true about heat. 1. Heat always flows from cooler to warmer substances. 2. Heat doesn’t flow betwee

Oksana_A [137]

heat flows from the warmer body to the cooler body

7 0

3 years ago

Read 2 more answers

What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances

belka [17]

The given question is incomplete. The complete question is:What is the relative atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances.

Isotope mass amu Relative abundance

1 77.9 14.4

2 81.9 14.3

3 85.9 71.3

Express your answer to three significant figures and include the appropriate units.

Answer: 84.2 amu

Explanation:

Mass of isotope 1 = 77.9

% abundance of isotope 1 = 14.4% = $\frac{14.4}{100}=0.144$

Mass of isotope 2 = 81.9

% abundance of isotope 2 = 14.3% = $\frac{14.3}{100}=0.143$

Mass of isotope 3 = 85.9

% abundance of isotope 2 = 71.3% = $\frac{71.3}{100}=0.713$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(77.9\times 0.144)+(81.9\times 0.143)+(85.9\times 0.713)]$

$A=84.2amu$

Therefore, the average atomic mass of a hypothetical element that consists isotopes in the indicated natural abundances is 84.2 amu

4 0

3 years ago

2 bromocyclopentanamine structural formula

Elis [28]

Answer:

The structure is given in attached file.

Explanation:

Explanation

2-bromocyclopentamine (Figure attached) is a synthetic compound which is synthesized by substitution reaction of cyclopentamine and hydrobromide. Its molecular formula and molecular mass are C5H10NBr and 164.05 mol/g respectively. It is a very reactive compound so it doesn’t available in pure form, it is present in market as a mixture of 2-bromocyclopentamine and Hydrobromide.

Properties :

Its boiling point is 115 0C

Its melting point is – 75 oC

It is highly flammable

It is highly toxic

It is irritant

It is corrosive in nature

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3 years ago