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Whitepunk [10]
3 years ago
15

What is the factored form of n2 – 25? (n – 25)(n – 1) (n – 5)(n + 5) (n + 5)(n + 5) (n – 25)(n + 1)

Mathematics
1 answer:
dexar [7]3 years ago
5 0
Hi there!
We are asked to find the correct factored form of n² - 25. Immediately, we can see that 25 has a perfect square root, 5. Now, we can rewrite the expression into n² - 5². Finally, using the difference of squares rule, we can derive the equation (n + 5)(n - 5). Therefore, the answer is (n + 5)(n - 5). Hope this helped!
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It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
2 years ago
Cedarburg's zoo has two elephants. The male elephant weighs 3 3/4 tons and the female
gtnhenbr [62]

Answer:

3.16666667 tons

Step-by-step explanation:

hope this helps have a good evening

3 0
2 years ago
Describe the end behavior of f(x) = - 2 ^ (x + 3) - 1
PilotLPTM [1.2K]

Answer: the answer is an equation

Step-by-step explanation:

4 0
3 years ago
A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location. At its Milford location, the
Vlad1618 [11]

Answer:

Milford location has a higher ratio of hamsters to gerbils.

Step-by-step explanation:

Given:

A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location.

At its Milford location, there are 13 hamsters and 16 gerbils.

Now, to find the location who has a higher ratio of hamsters to gerbils.

Ratio of hamsters to gerbils at Lanberry location = 5:10.

=\frac{5}{10}=0.50

                                                                         

Ratio of hamsters to gerbils at Milford location= 13:16.

=\frac{13}{16} =0.8125

                                                       

<em>So, 0.8125 > 0.50.</em>

<em>Thus, </em><u><em>13:16 > 5:10.</em></u><em> </em>

Therefore, Milford location has a higher ratio of hamsters to gerbils.

4 0
3 years ago
A game designer must decide how to color four buildings that are in a row. Using only the colors yellow, green, red, and blue, e
topjm [15]

Answer:

The number of ways are there to paint the four buildings is 48.

Step-by-step explanation:

I) let the first building be any color. Therefore the first building can be painted with any of the 4 colors.

Therefore the first building can be colored in 4 ways.

ii) the second building can be colored in 3 ways since it cannot be colored the

same color as the first building.

iii) the third building can also be colored in 3 ways.

iv) the last building can be colored in 2 ways because it cannot be the same color as the first building or the color of the adjacent building.

Therefore the total number of ways the buildings can be colored = 4 \times 3 \times 3  \times 2 = 48.

7 0
3 years ago
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