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ddd [48]
4 years ago
14

63x^20y^16/3x^9y^15 helllp

Mathematics
2 answers:
Nuetrik [128]4 years ago
7 0
Did that information help

aksik [14]4 years ago
5 0
\frac{63x^{20}y^{16}}{3x^{9}y^{15}}=\frac{63}{3}\frac{x^{20}}{x^{9}}\frac{y^{16}}{y^{15}}=\frac{21}{1}\frac{x^{17}}{1}\frac{1}{y}=\frac{21y^{17}}{y}
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Which best describes the range of the function f(x)=2/3(6)x after it has been reflected over the x axis
shtirl [24]
The range is all real numbers.

The function given simplifies to just f(x) = 4x.

This is just a straight line that is increasing from left to right. If we reflect the line over the x-axis, it is still a line that goes on forever in each direction.

Therefore, the range will be all real numbers.
4 0
3 years ago
Read 2 more answers
Find an equation of variation in which y varies directly as x and y=1 when x=0.5. Then find the value of y when x = 14.
FromTheMoon [43]

<u>Part 1</u>

The value of y is twice that of x, so the equation is y = 2x.

<u>Part 2</u>

Substituting in x = 14, we get y = 2(14) = 28.

8 0
2 years ago
Ben, sean, alexis and samantha divide a $47 so that ben and sean together got $27, ben and alexis got $25, and ben and samantha
ELEN [110]

Answer:

$11

Step-by-step explanation:

Let Ben has b,

sean has s

alexis has a

samantha has s

Money.

We need to write the words into equations and solve as we can.

b + s + a + s = 47

b + s = 27

b + a = 25

b + s = 23

We need to find a.

Let's put 2nd equation in first, to get:

27 + a + s = 47

a + s = 20 ---------- 5th equation

Now let's solve 4th equation for b and put it into 3rd equation:

b + s = 23

b = 23 - s

Putting in 3rd equation:

23 - s + a = 25

a - s = 2 ---------------6th equation

Now, add up 5th and 6th equation to get a:

a + s = 20

a - s = 2

-------------

2a = 22

a = 22/2 = 11

Alexis got $11

8 0
3 years ago
The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation
rodikova [14]

Answer: C) y=sin^-1 x

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point (1,\frac{\pi}{2}),

If this point satisfies the function,

For the function y=cos^{-1} x

If x = 1

y=cos^{-1}1=0

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=cos^{-1} x is not passing through the point  (1,\frac{\pi}{2})

For the function y=cot^{-1}x

If x = 1

y=cot^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function y=cot^{-1}x,

⇒ The graph of   y=cot^{-1}x is not passing through the point  (1,\frac{\pi}{2})

For the function y=sin^{-1} x

If x = 1

y=sin^{-1}1=\frac{\pi}{2}

Thus,  (1,\frac{\pi}{2}) is satisfying function y=sin^{-1} x,

⇒ The graph of   y=sin^{-1} x is passing through the point  (1,\frac{\pi}{2}).

For the function y=tan^{-1}x

If x = 1

y=tan^{-1}1=\frac{\pi}{4}

Thus,  (1,\frac{\pi}{2}) is not satisfying function  y=cos^{-1} x,

⇒ The graph of   y=tan^{-1} x is not passing through the point (1,\frac{\pi}{2}).

Hence, Option C is correct.

3 0
3 years ago
How many degrees is 7/4 of a semicircle?
Alexxandr [17]

Answer:

315

Step-by-step explanation:

7/4 of 180°

= 1.75 * 180

= 315°

5 0
2 years ago
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