Erosion of sand n dirt and it ca cause sinkholes
In the F<span>1 </span>generation of a Mendelian cross,
only the dominant trait is visible.only the recessive trait is visible.neither the dominant nor recessive trait is visible.<span>both the dominant and recessive traits are visible.
-I believe the correct answer is "ONLY THE DOMINANT TRAIT IS VISIBLE" in F1 generation, it is when the two true breeds, both homo (same genes) cross for example, HH and hh, since H will always be present in a punnet square, the answer is ONLY THE DOMINANT TRAIT IS VISIBLE. key word VISIBLE, the dominant trait is H</span>
Answer:
A= 20%
G= 30%
T= 20%
C= 30%
Explanation:
Recall that the sum of all nitrogenous bases in the DNA nucleotide is equal to 100%. And specific base pairings of Adenine to Thymine (A=T), and Cytosine to Guanine (C=G) must be equal.
So, the percentage of Adenine equal thymine, and that of cytosine equals guanine.
Now, A + T + C + G = 100%
So, if Adenine makes up 20% of the DNA nucleotides, Thymine is also 20%.
Then, 20% + 20% + C + G = 100%
40% + C + G = 100%
C + G = 100% - 40% = 60%
So, divide 60% by 2 to obtain the individual percentage of cytosine and guanine. Each will take 30%
Finally, A= 20%; G= 30%; T= 20%; C= 30%
Lane A.
The smallest fragments of DNA will be witnessed near the bottom of the gel, on the other hand, the heavier fragments will be visible at the top. The theory behind this is there is a specific pore size on the basis of the concentration of acrylamide/agarose in the gel.
Protons- these have a positive charge
Electrons-negative charge
Neutrons- neutral charge
