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Free_Kalibri [48]
3 years ago
8

Determine the number of protons for K-40

Physics
1 answer:
inna [77]3 years ago
6 0
I think there is 19 protons
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The siren on an ambulance emits a sound of frequency 2.80×103Hz. If the ambulance is traveling at 26.0 m/s (93.6 km/h or 58.2 mi
Norma-Jean [14]

To solve this problem it is necessary to apply the concepts related to the described wavelength through frequency and speed. Mathematically it can be expressed as:

\lambda = \frac{v}{f}

Where,

\lambda = Wavelength

f = Frequency

v = Velocity

Our values are given as,

f = 2.8*10^3Hz

v = 340m/s \rightarrow Speed of sound

Keep in mind that we do not use the travel speed of the ambulance because we are in front of it. In case it approached or moved away we should use the concepts related to the Doppler effect:

Replacing we have,

\lambda = \frac{340}{2.8*10^3}

\lambda = 0.1214m

Therefore the frequency that you hear if you are standing in from of the ambulance is 0.1214m

5 0
3 years ago
A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what is the y-component of the normal force?
Rama09 [41]

Answer:

The y-component of the normal force is 45.74 N.

Explanation:

Given that,

Mass of the crate, m = 5 kg

Angle with hill, \theta=21^{\circ}

We need to find the y component of the normal force. We know that the y component of the normal force is given by :

F_y=F\ \cos\theta\\\\F_y=mg\ \cos\theta\\\\F_y=5\times 9.8\ \cos(21)\\\\F_y=45.74\ N

So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.

7 0
3 years ago
Electromagnetic waves differ fundamentally from either water or sound waves because they
stepladder [879]
<span>Electromagnetic waves differ fundamentally from either water or sound waves because they does not require any medium, they can travel in free space (vacuum) 

Hope this helps!</span>
8 0
3 years ago
A car travels a distance of 540km in 6hours.What speed did he travel at?​
Sloan [31]

Answer: 90 km/hr

Explanation:

Speed= distance divided by time

540/6

= 90km/hr

5 0
3 years ago
A rope breaks when the tension reaches 205 N. What is the maximum speed at which it can swing a 0.477 kg mass in a circle of rad
jekas [21]

Answer:

Maximum velocity will be 17.651 m /sec

Explanation:

We have given a rope breaks when tension reaches 205 N

Mass m = 0.477 kg

Radius of the circle r = 0.725 m

Tension in the rope is given by

T=\frac{mv^2}{r}

205=\frac{0.477\times v^2}{0.725}

0.477v^2=148.625

v^2=311.5828

v = 17.651 m /sec

8 0
4 years ago
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