Answer: mechanical energy
Explanation: I hope this helps! Also, please mark as brainliest, thanks!
The one the measures using a computer spreadsheet and holds the flask at eye level and uses the correctly calibrated scale
The truck in the lead is covering 50 miles in one hour.
The car behind is covering 70 miles in one hour.The car is covering 20 miles more than the truck in one hour.So the car gets 20 miles closer to the truck in one hour.
Since they were 20 miles apart at the beginning of the story, one hour is enough time for the car to catch up to the truck.
Answer:
D) Joe need to walk 481 m in a direction 40.9° north of east
Explanation:
Given:
1. Walk 300 m north
2. Walk 400 m northwest
3. Walk 700 m east-southeast and the treasure is buried there
Taking north as positive y axis and east as positive x axis.
Resolving their positions into x and y vector components.
1. d1 = 300j
2. d2 = -400cos45i + 400sin45j
3 d3 = 700cos22.5i - 700sin22.5j
Resultant position.
d = d1+d2+d3
d = (-400cos45 + 700cos22.5)i + (300+400sin45-700sin22.5)j
d = (363.873)i + (314.964)j
D = √( (363.873)^2 + (314.964)^2)
D =481.25m ~= 481m
Angle = taninverse (314.964/363.873)
Angle = 40.9°
Since the x and y components are both positive, it implies that their position is north of east
Therefore, Joe need to walk 481 m in a direction 40.9° north of east
Given: Altitude of satellite r = 13,300 Km convert to meter
r = 1.33 x 10⁷ m
Universal Gravitational constant G = 6.67 x 10⁻¹¹ N.m²/Kg²
Mass of the earth Me = 5.98 x 10²⁴ Kg
Required: Period of satellite T = ?
Formula: F = ma; Centripetal acceleration ac = V²/r F = GMeMsat/r²
Velocity of satellite V = 2πr/T
equate T from all given equation.
F = ma
GMeMsat/r² = MsatV²/r cancel Msat and insert V = 2πr/T
GMe/r² = (2πr)²/rT² Equate T or period of satellite
T² = 4π²r³/GMe
T² = 39.48(1.33 X 10⁷ m)³/(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)
T² = 9.29 x 10²² m³/3.99 x 10¹⁴ m³/s²
T² = 232,832,080.2 s²
T = 15,258.84 seconds or (it can be said around 4.24 Hr)
