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Irina-Kira [14]
1 year ago
12

light that is polarized along the vertical direction is incident on a sheet of polarizing material. only 87% of the intensity of

the light passes through the sheet. what angle is the axis of the polarizer oriented, with respect to the vertical?
Physics
1 answer:
nekit [7.7K]1 year ago
8 0

Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.

A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.

given

Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.

Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is

θ₂ = θ₁ + 90°

   = 31.94° + 90°

   = 1 21.94°

for the first sheet and

Icos²θ₁ = I

I/I₀ = 0.72

θ₁ = cos⁻¹√(0.72)

    = 31.94°

for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.

To know more about light that is polarized, click on the link below:

brainly.com/question/3092611

#SPJ4

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Answer:

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Explanation:

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Using formula of collision

v_{1}=(\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}})u_{1}+(\dfrac{2m_{2}}{m_{1}+m_{2}})u_{2}

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v_{1}=(\dfrac{0.5-2.30}{0.5+2.30})\times3.13

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Negative sign shows the opposite direction of initial direction.

(b). We need to calculate the speed of the block after collision

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v_{2}=(\dfrac{2m_{1}}{m_{1}+m_{2}})u_{1}+(\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}})u_{2}

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(b). The speed of the block after collision 1.11 m/s.

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